293 is already prime. Those numbers don't exist.
The sum of two numbers is those two numbers multiplied together. For instance, the sum of 4 and 5 is 20.
Multiplying two numbers together will create a common multiple. It is sometimes, but not always, the LCM as well.
They cannot be integers or whole numbers; but they can be numbers with decimals. There are many possibilities; if the numbers are the same, then that is the square root of 10000000 which is 3162.277666...repeating. Those same numbers multiplied together = 10000000. If numbers are different, there are other combinations, all involving decimals
The numbers are: -27+6*sq rt of 14 and -27-6*sq rt of 14
Those numbers are called factors. A pair of those is called a factor pair.
1*(-5) 5*(-1) Those are the only two whole number equations that equal (-5). If you are looking for more than just whole numbers any two numbers you can multiply to equal positive 5, if you make one value negative your product will become negative. (i.e. 2*2.5=5 | (-2)*2.5=(-5))
A product of two integers is those two numbers multiplied together. If the product is two integers, it is called a square. Two negative integers are multiplied together by multiplying them together just as if they are positive. For example, -3x-3=9. It is exactly the same thing as squaring a positive integer.
25 and 54
741 results from the following multiplications of two numbers: 1 * 741 (1 is not prime) 3 * 247 (247 is not prime) 13 * 57 (57 is not prime) 19 * 39 (39 is not prime) There are no two prime numbers that when multiplied equal 741. 3 * 13 * 19 equals 741, and all three of those numbers are prime.
Those are 'factors'.
2009=7x7x41 and those are all primes.
I just did a very similar problem where you have to find a set of numbers so that when multiplied or added together you get 7. So i just plugged in your 7.11 into my formula and got an answer. Its a bit complicated how I got there. Essentially I used the formula a/b+(a-b)/b+b^2=(whatever number you want). And the formula a/b*(a-b)/b*b^2=(the number you want). Then I plugged in 7.11, combined the two formulas to solve for b. Used my calculator to find the solution (which should be in terms of fourth roots and square roots) and got these numbers. (they are rounded) a=3.121604582 b=.84392981. Notice that each of those equations uses 3 terms (a/b, (a-b)/b, b^2). Those are the three numbers. So finally, the numbers are... 3.698891237, 2.698891237, .7122175253. If you want whole numbers though... I cant help.
3 cubed is 3^3=27 and 5 squared is 5^2=25. A cube of an integer is that integer multiplied by itself three times. A square of an integer is that integer multiplied by itself two times. The average of two numbers is those two numbers added together and divided by two. Any average is the numbers added together, then divided by the number of integers. Therefore, the average is (27+25)/2=52/2=26.
You can calculate the sum of numbers by adding numbers together. You can calculate the product of numbers by multiplying those numbers.
Normally, you would do this by finding a pair of numbers whose product is equal to the product of the first term's coefficient multiplied by the last term, and whose sum is equal to the coefficient of the second term. Those numbers could then be used to break the expression down further. In other words, you are looking for two numbers, we'll call them A and B, in which (A + B) = -4 and AB = 5. Unfortunately, there are no such numbers, so that expression can not be factored.
If you mean "factorize" than this is my favourite method. Take this standard equation: X^2-12X+35 All you need to do is find two numbers which when added together equal -12 and when multiplied together equal 35. -5 and -7 can be added to make -12 -5 and -7 can be multiplied to make 35 Now that you have your two numbers, this is how you write them in a factored equation: Y=(X-5) (X-7) And that's your factored equation! NOTE: Those 2 numbers are also your "zeroes" or "x-intercepts" on your parabola. But when you use them on your graph, YOU MUST CHANGE THEIR SIGNS! So as zeroes they would be positive 5 and 7 rather than negative. (5,0) (7,0) Good luck.
They can. The text numbers are 0-9 and if you add 0 and 2 then they equal 2. Those are the only two numbers that will work though.