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What 3 digit numbers have a remainder of 3 when divided by 5 and a remainder of 2 when divided by 7 how many did you find?
Wiki User
∙ 10y ago
Least: 128
By adding 35 to 128, there is (999-128)/35 ≈ 24 numbers:
128, 163, 198, 233, 268, 303, 338, 373, 408, 443, 478, 513, 548, 583, 618, 653, 688, 723, 758, 793, 828, 863, 898, 933, 968.
Wiki User
∙ 10y ago
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Does 4554 divided by 9 have a remander?
506
What is the remainder of 53 divded by 9?
The remainder is 8. To find the remainder when a number is divided by 9, add the digits together; if this sum has more than 1 digit, repeat until one digit remains. This digit is the remainder, unless it is 9 in which case the remainder is 0. examples: remainder 53 → 5 + 3 = 8 → remainder is 8 when 53 is divided by 9. remainder 126 → 1 + 2 + 6 = 9 → remainder is 0, ie no remainder, 126 is divisible by 9. remainder 258 → 2 + 5 + 8 = 15 → 1 + 5 = 6 → remainder is 6 when 258 is divided by 9.
What is the units digit in 3 power 2011?
I guess you mean what's the units digit of 32011. It is 7. To work this out, see how the units digit of 3n changes; it goes: 3, 9, 7, 1, 3, 9, 7, 1, ... (only the first 8 powers are shown) repeating the same sequence of 4 digits. So if we find the remainder of 2011 divided by 4, it will tell us which of the four numbers (3, 9, 7, 1) will be the units digit of 32011: 2011 ÷ 4 ⇒ remainder 3, so the 3rd digit is the required digit: 7. (If there had been no remainder, then the 4th digit, namely 1, would have been the required value.)
How can you find the 2001st digit of a recurring decimal?
Assume the decimal starts recurring immediately after the decimal point. (If the recurring string starts after k digits, then you want to find the (2001-k)th digit instead.) Find the length of the recurring string = L Find the remainder when 2001 is divided by L = R The 2001st digit is the Rth digit in the recurring string.
What numbers can be divided by 36?
Any number can be divided by 36 but most will give a remainder. To find all the numbers which when divided by 36 do not give a remiander use the formula 36n where n is any positive integer.
Does 4554 divided by 9 have a remander?
506
What is the remainder of 53 divded by 9?
The remainder is 8. To find the remainder when a number is divided by 9, add the digits together; if this sum has more than 1 digit, repeat until one digit remains. This digit is the remainder, unless it is 9 in which case the remainder is 0. examples: remainder 53 → 5 + 3 = 8 → remainder is 8 when 53 is divided by 9. remainder 126 → 1 + 2 + 6 = 9 → remainder is 0, ie no remainder, 126 is divisible by 9. remainder 258 → 2 + 5 + 8 = 15 → 1 + 5 = 6 → remainder is 6 when 258 is divided by 9.
Can there be a two digit remainder in a one digit answer?
A remainder is what's left after a division. If I can find a sum that has a one digit answer but a two digit remainder, I've proven it's possible. 915/100= 9 with a remainder of 15. One digit answer, two digit remainder. So, yes, it's possible.
How many different 2 digit numbers can you find that have remainder 2 when each is divided by 6?
14, 20, 26, 32, 38, 44, 50, 56, 62, 68, 74, 80, 86, 92, and 98
How do you find the common factor in numbers?
You determine all numbers that will can be divided evenly (without a remainder) into the object numbers. The highest number doing that is the common factor.
How do you find the remainder of 245 divided by 7?
35
When the middle digit of a three-digit number N is removed the two digit number thus obtained is N divided by 16 Find all such numbers N?
160 and 192.
What numbers can be divided by 36?
Any number can be divided by 36 but most will give a remainder. To find all the numbers which when divided by 36 do not give a remiander use the formula 36n where n is any positive integer.
What is the units digit in 3 power 2011?
I guess you mean what's the units digit of 32011. It is 7. To work this out, see how the units digit of 3n changes; it goes: 3, 9, 7, 1, 3, 9, 7, 1, ... (only the first 8 powers are shown) repeating the same sequence of 4 digits. So if we find the remainder of 2011 divided by 4, it will tell us which of the four numbers (3, 9, 7, 1) will be the units digit of 32011: 2011 ÷ 4 ⇒ remainder 3, so the 3rd digit is the required digit: 7. (If there had been no remainder, then the 4th digit, namely 1, would have been the required value.)
How can you find the 2001st digit of a recurring decimal?
Assume the decimal starts recurring immediately after the decimal point. (If the recurring string starts after k digits, then you want to find the (2001-k)th digit instead.) Find the length of the recurring string = L Find the remainder when 2001 is divided by L = R The 2001st digit is the Rth digit in the recurring string.
Find the remainder when 21990 is divided by 1990?
11.0503
What is the remainder when you find 638 divided by 5?
127.6
