The numbers are 0, 2, 4, 6, 8 and 10.
The integers are 6, 7, 8 and 9.
They are 5 and 6
The consecutive integers of 6 are the numbers that come immediately before and after it. These integers are 5, 6, and 7. If you consider a broader range, the consecutive integers around 6 can include any integer in the sequence, such as 4, 5, 6, 7, and 8.
Consecutive integers are ...-3,-2,-1,0,1,2,3...One right after the other.Two consecutive integers would be 5 and then one more, 6.
It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16
The integers are 6, 7, 8 and 9.
THere are two pair of consecutive integers. 52 = 25 < 30 < 36 = 62 So, one pair is 5 and 6 and the other pair is -6 and -5.
They are 5 and 6
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
The numbers are 6, 7, 8 and 9.
The consecutive numbers are 6, 7, 8 and 9.
Consecutive integers are ...-3,-2,-1,0,1,2,3...One right after the other.Two consecutive integers would be 5 and then one more, 6.
Start with "-3", then add one at a time to get as many consecutive integers as you want.
It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16
2, 3, 4 and 5.
Let x equal the smallest integer. The sum will be 3x + 6
6,12,18.