You can do this by trial-and-error.Or, call one integer "n", the next one "n+1", and solve the equation:
n(n+1) = 440
Note: Whichever of these two methods you use, it will be clear that this problem has no integer solution.
There are no such numbers.
There are no such integers. 20*21 = 420 is too small while 21*22 = 462 is too large.
As the product of its prime factors: 2*2*2*5*11 = 440 or as 23*5*11 = 440
Any number (positive or negative) minus zero is just the original number. e.g. 3 - 0 = 3 -440 - 0 = -440 -2 - 0 = -2 What you are really saying here is take away nothing from a number.
440 = 2 x 2 x 2 x 5 x 11 OR 23 x 5 x 11
440 = 11 * 40= 11 * 5 * 8= 11 * 5 * 2 * 4= 11 * 5 * 2 * 2 *211, 5, and 2 are all prime numbers.
There are no two consecutive integers, negative or positive, whose product is 440.
I think you mean consecutive even integers: 20 & 22
There are no such integers. 20*21 = 420 is too small while 21*22 = 462 is too large.
Multiply 440 x .07 and then add the product to 440: (440 x .07) + 440 = 30.80 + 440 = 470.80
The product is 440
As the product of its prime factors: 2*2*2*5*11 = 440 or as 23*5*11 = 440
2 x 2 x 2 x 5 x 11 = 440
Any number (positive or negative) minus zero is just the original number. e.g. 3 - 0 = 3 -440 - 0 = -440 -2 - 0 = -2 What you are really saying here is take away nothing from a number.
440 = 2 x 2 x 2 x 5 x 11 OR 23 x 5 x 11
440 + 440 + 440 + 440 + 440 + 440 = 2,640
0.000 000 000 000 810 440 156
440