i am not sure
chances of rolling doubles = 1/6 (assuming you are using a six-sided die) chances of rolling doubles 7 times in a row = (1/6)^7, or 0.0003572%
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
25/36
The probability of rolling a six with a standard die five times in a row is (1 in 6)5 which equals 1 in 7776 or about 0.0001286.
Suppose A is the event {rolling a 6-sided die 20 times and getting a 5} Then A', the complement of A, is the event {rolling a 6-sided die 20 times and not getting a 5 any times} So Pr(A) = 1 - Pr(A') = 1 - (5/6)20 = 1 - 0.026084 = 0.973916 (to 6 dp)
00
1 in 6 times 1 in 6 equals 1 in 36
1/6 times 1/6 times 1/6= 1/216 chance of getting a 4.
25.00
The chance of rolling a 6 twice in a row, on a six-sided die, is 1 in 36 or 2.78%. The number of possible different results for rolling a six-sided die twice is 6 squared (6 times 6), or 36, therefore the probability of getting any one of the possible results is 1 out of 36.
chances of rolling doubles = 1/6 (assuming you are using a six-sided die) chances of rolling doubles 7 times in a row = (1/6)^7, or 0.0003572%
1 in 100000000000000000000000000 or 10^26
If the dice is 6 sided, the chances of rolling each number is about 17% (100/6) If the dice is 4 sided, the chances of rolling each number is 25% (100/4) Similarly, 8 sided = 12.5% 10 sided = 10% 12 sided ≈ 8% 20 sided = 5%
The probability is (0.1) times (the number of faces with '4' marked on them).
It is 0.1962
It is 0.99999406 approx, or pretty nearly a certainty.