The factor pairs of 72 are (72,1)(36,2)(24,3)(18,4)(12,6)(9,8)
None of them total 6. If that was -72, you could use 12 and -6.
-8 -9
71+72=143
72
The answer is 72! :)
1,1,72 1,2,36 1,4,18 1,3,24 1,6,12 2,2,18 1,8,9 2,3,12 2,4,9 2,6,6 3,4,6 there is more too but that all I could think of
The two consecutive even integers whose sum is 72 are 36 and 38.
The even integers are 22, 24 and 26.
-8 -9
The numbers are -21, -19, -17 and -15.
The numbers are 8 and 9.
Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37
The sum of 72 and 12 is 84. The product of the two numbers is 864.
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
The sum of three consecutive integers is -72
72/3 = 24 and 7+8+9 = 24 so the integers are 7, 8 and 9.
The numbers are 23, 24 and 25.
ANSWER: 12 and -6x * y = 72x = 72/y Equation 1x + y = 6 Equation 2Substitute Eq.1 to Eq.2-72/y + y = 6multiply both sides of the equation by yy (-72/y + y ) = 6* y-72 + y2 = 6yy2 - 6y - 72 = 0(y- 12) (y + 6) = 0y = 12 ; y = -6x =-12 ; x = 12Take x = 12 and y = -6