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First find the least common multiple. To do this, prime factorize them all; we have: 3, 22, 5, and 2 * 3. Each factor is included in the final factorization as often as in each occurs the most. Thus we have 22 * 3 * 5 = 60. Therefore, any multiple of 60 is a multiple of 3, 4, 5, and 6.

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16y ago

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