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First of all, you need to be more specific. It's three consecutive integers. And they are 2,999, 3,000, and 3,001

Q: What are 3 numbers that are in a row and have the sum of 9000?

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20.800838230519041145300568243579 * 20.800838230519041145300568243579 * 20.800838230519041145300568243579 = 9000

usually the largest on the top row of the sum, then the middle, then the smallest, makes a tidier arrangement

You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).

(2) x (3) x (1,500.1) will do it.

The sum = 2r : where r is the row number.

Related questions

n+n+1+n+2=9000 3n+2=9000 3n=9000-2 3n=8997 n=8997/3 n=2999 n+1=3000 n+2=3001

18 + 19 + 20 = 57

199,200 and 201 because 199+200+201=600

the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc.......... the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc..........

20.800838230519041145300568243579 * 20.800838230519041145300568243579 * 20.800838230519041145300568243579 = 9000

First, you didn't enter the numbers correctly...Row 1: 1Row 2: 3, 5Row 3: 7, 9, 11Row 4: 13, 15, 17, 19 (you were missing the 19)Row 5: 21, 23, 25, 27, 29To get an idea of the answer to the first question, continue the pattern a couple more rows, focusing on the middle number(s)...Row 1: 1Row 2: 3, 5Row 3: 7, 9, 11Row 4: 13, 15, 17, 19Row 5: 21, 23, 25, 27, 29Row 6: 31, 33, 35, 37, 39, 41Row 7: 43, 45, 47, 49, 51, 53, 55If you've studied median, you know it's the middle number when the data is arranged in order, and that if there are two "middle" numbers, the median is the mean of the two numbers (i.e. median of row 4 is (15 + 17)/2 = 16).Median ofRow 1 is 1Row 2 is 4Row 3 is 9Row 4 is 16Row 5 is 25Row 6 is 36Row 7 is 49The median of each row is the square of the row number (i.e. row 6... 6^2 = 6*6 = 36)So you can infer that the median (middle number) in the 99th row would be 99 squared, which is 9801.For the second part of the question, examine the sums of the numbers in each row...Row 1: 1 Sum = 1Row 2: 3, 5 Sum = 8Row 3: 7, 9, 11 Sum = 27Row 4: 13, 15, 17, 19 Sum = 64Row 5: 21, 23, 25, 27, 29 Sum = 125The pattern to recognize here is that the sum of the numbers in each row is the cube of the row number (i.e. Row 3... 3^3 = 3*3*3 = 27)So you can infer that the sum of the numbers in the 30th row is 30 cubed, which is 27,000.

usually the largest on the top row of the sum, then the middle, then the smallest, makes a tidier arrangement

3

(2) x (3) x (1,500.1) will do it.

You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).You add the numbers. Then you divide by the number of numbers (i.e., if you have three numbers, you divide the sum by 3).

Sorry. No sum of even numbers can be an odd number.

What to whole numbers have a sum of 12 and quotient of 3?