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one die, the numbers 1,2,3,4,5 or 6, two dice, the 1,1 1,2 1,3 1,4 1,5 1,6 2,1 etc. There are 36 outcomes
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How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin and rolling a die?
The answer is 12 APEX ✨
How many leaves on a tree diagram are needed to represent all possible combinations of rolling a die and spinning a spinner with 8 sections?
48
When rolling a pair of dice what is the probability that it will land on 11 or 12?
There are 36 possible combinations of rolling 2 die. To get an 11 or 12, the rolls would be 5, 6 or 6, 5 or 6,6 which is 3 possible correct outcomes, So, the probability of landing on an 11 or 12 is 3/36 or 1/12.
When rolling a sixsided die a possible event is rolling a sum which is a multiple of 5 What is the probability of this event?
The probability of rolling a multiple of five on a standard die is 1 in 6, or about 0.1667.The probability of rolling a 10, 15, or higher is zero, because the question implied only one die.
What is the size of the sample space for all the outcomes possible from rolling four dice?
There is 6 possible outcomes per roll of a die. So, there are 6*6*6*6 outcomes or 64 or 1296 possible outcomes.
How many leaves on a tree diagram are needed to represent all possible combinations tossing a coin and rolling a die?
The answer is 12 APEX ✨
How many leaves on a tree diagram are needed to represent all possible combinations of rolling a die and spinning a spinner with 8 sections?
48
What is the probability of rolling two 2's on two six-sided die?
The chance is 1/36. (There are 36 possible combinations for two 6-sided dice, but only 18 separate combinations when the dice are not considered seperately.)
What are the odds of rolling two die with one landing on a 5 and the other landing on a 1?
there are 36 possible combinations in two single die tosses. The odds of any one combination is then 1:36
When rolling a pair of dice what is the probability that it will land on 11 or 12?
There are 36 possible combinations of rolling 2 die. To get an 11 or 12, the rolls would be 5, 6 or 6, 5 or 6,6 which is 3 possible correct outcomes, So, the probability of landing on an 11 or 12 is 3/36 or 1/12.
How many possible outcomes of rolling a ten-sided die?
If the numbers (or symbols) are all different then 10 outcomes.
What is the probability of rolling an odd number OR getting a heads when rolling a die and tossing a coin?
To find the probability that when rolling a die and tossing a coin, your will obtain an odd on the die OR a heads on the coin, use the addition rule, which is: P(A) + P(B) - P(A and B) = P(A or B In this example, event A is tossing heads on the coin, and event B is rolling odd on the die. What you are trying to solve is actually A U B (A union B) First the sample set of all 12 possible combinations: S={H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6} The 6 heads possible combinations are: A={H1, H2, H3, H4, H5, H6| The 6 odd number possible combinations are: B={H1, H3, H5, T1, T3, T5} The 3 combinations these sets have in common, A intersect B: A n B= {H1. H3, H5} There are 12 possible combinations and 6 of those include a heads on the coin. This is 6/12. There are 12 possible combinations and 6 of those include an odd on the die. This is 6/12. There are 12 possible combinations and 3 of those include both an odd on the die, and a heads on the coin. This is 3/12. 6/12 + 6/12 - 3/12 = 9/12 Simplify the above number to 3/4, which is the correct answer to this question. If you draw a Venn diagram, you will see that the set consisting of tails and evens {T2, T4, T6} falls outside the circles. The diagram makes it easy to see that 9 of the 12 possible combinations fall inside the circle, and 3 of the 12 fall outside. Hope this helps someone. I solidified the information for myself by writing it!
How many possible outcomes are there when rolling 1 six sided die?
Six.
When rolling a sixsided die a possible event is rolling a sum which is a multiple of 5 What is the probability of this event?
The probability of rolling a multiple of five on a standard die is 1 in 6, or about 0.1667.The probability of rolling a 10, 15, or higher is zero, because the question implied only one die.
You roll a red die and a green die What is the size of the sample space of all possible outcomes of rolling these two dice given that the red die sHow is an even number?
25 percent
Which can not be used to display all the possible outcomes for rolling a fair die and spinning a spinner numbered 1 through 8?
A banana cannot be used.
What is the size of the sample space for all the outcomes possible from rolling four dice?
There is 6 possible outcomes per roll of a die. So, there are 6*6*6*6 outcomes or 64 or 1296 possible outcomes.
