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Q: What are every possible 4 digit combinations of the numbers 0 through 9?

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Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.

56 combinations. :)

There is only one combination since the order of the numbers in a combination does not matter.

There are 720 of them!

90

This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.

im not geeky enough to answer that

Number of 7 digit combinations out of the 10 one-digit numbers = 120.

The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.

7

The number of four-digit combinations is 10,000 .Stick a '3' before each of them, and you have all the possible 5-digit combinations that start with 3.There are 10,000 of them. They run from 30,000 to 39,999 .

Exactly 3,628,800, or 10!.

There are 38760 combinations.

There are 9999 possible combinations starting from 0000 to 9999

it depends on which 8 numbers your talking about

We can use 36 characters for each of the slots in the combination. Therefore, we have 36^11 possible combinations, or 131,621,703,842,267,136 combinations.

It is: 9C7 = 36

66

15

10,000

2304

16

Without restrictions, it was would numbers 000-000-0000 through 999-999-9999. So that would be 9,999,999,999 + 1 = 10 billion different 10-digit phone numbers. Ex: If there existed single digit phone numbers, there would be 10, because the digits are 0 through 9. If there existed only double digit phone numbers, then it would be 00 through 99 which would be 100 total two-digit numbers. Therefore the total possible combinations for an X digit phone number would be: 10^X

There are 10,000 4 digit combinations possible with the Digits 0-9

Passwords are technically permutations, not combinations. There are 104 = 10000 of them and I regret that I do not have the time to list them. They are all the numbers from 0000 to 9999.