Q: What are prime factors of 630?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

is the answer (1,2,3,5,6)

As a product of its prime factors: 2*32*5*7 = 630

It is: 2*3*3*5*7 = 630

First you separate it into prime factors (start looking for small factors, such as 2, 3, 5). Then, you combine the factors with exponents.

630 has 24 factors.

Related questions

is the answer (1,2,3,5,6)

As a product of its prime factors: 2*32*5*7 = 630

It is: 2*3*3*5*7 = 630

As a product of its prime factors: 2*3*3*5*7 = 630

2 x 3 x 3 x 5 x 7 = 630

As a product of its prime factors: 2*3*3*5*7 = 630

First you separate it into prime factors (start looking for small factors, such as 2, 3, 5). Then, you combine the factors with exponents.

The GCF of 735 and 630 is 105. To find the GCF of two numbers, you first have to split them into their prime factors. In this case, 735 and 630 can be broken down as follows: 735 = 3x5x7x7 630 = 2x3x3x5x7 The next step is to identify any common prime factors. In this case, both numbers have prime factors of one 3, one 5 and one 7. To find the HCF, we multiply these factors together: 3x5x7 = 105 Thus the GCF of 735 and 630 is 105.

The prime factors of 630 are 2 x 3 x 3 x 5 x 7

5

It is: 630 by finding the prime factors of the given numbers

The GCF of 630 and 910 is 70The prime factorization of 630 is 2*5*7*3*3The prime factorization of 910 is 2*5*7*13The common prime factors are 2*5*7 so the GCF is 70.