There is no such set of six consecutive numbers.
It is 260.
The numbers are 11, 12, 13, 14, 15 and 16.
11 + 12 + 13 + 14 + 15 + 16 = 81
999999 is six digits and odd.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
The prime factorization of 180 is 2x2x3x3x5. Six consecutive prime numbers do not exist in its factorization.
If you mean six consecutive INTEGERS, then the answer is Yes.
The 3 consecutive odd positive integers are 7, 9 and 11.
Six of them.
26 27 28
The sum of six odd numbers is never fifteen since 15 is odd and the sum of six even numbers is always even. However if "make" allows products: 1* 1 * 1 * 1 * 3* 5 = 15 ( I used * to mean multiply.)
-7, -5, -3, -1, 1 and 3
There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.
The numbers are -4, -2 and 0.
To figure this out, divide 96 by three, ignoring the remainder for now. This gives the number 30. The remainder is 6. Three consecutive numbers that add up to six are 1, 2 and 3. So the three consecutive integers are 31, 32, and 33.
10, 12, 14 are the consecutive even #'s that equal 36
Six of them.