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Suppose the rhombus is ABCD.

Consider the triangle ABC, whose area will be 40/2 = 20 sq cm.That is, 0.5*AB*BC*sin(B) = 20

sin(B) = 40/225 = 0.1777... recurring.

Therefore B = arcsin(1.777...) = 0.1787 or 2.9629 radians or equivalently, 10.24 or 169.76 degrees.

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Q: What are the angles of a rhombus with an area of 40 square centimeters and sides of 15 centimeters?
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