As the diagonals of a rhombus bisect the angles through which they pass and intersect at right angles, we now have 7 and 17 as the sides of the triangles. We have:
tan(x) = 7/17
x = arctan(7/17)
The half angle is about 22.38° and the full angle = 44.76°.
The angle of the second set of paired angles is therefore 180 - 44.76 = 135.24o
14M + 2n - 6M + 11n = 8M + 13n
17
1400cm
1400cm
If you mean: -8m+14m-8 then the given expression can be simplified to 6m-8
The length of one diagonal is not sufficient to determine its sides and so its perimeter.
10-14m = -4
43km 14m to kilometers
m² - 14m + 48 = (m - 6)(m - 8)
14M + 2n - 6M + 11n = 8M + 13n
Since 14m - 42 is a multiple of 7m - 21, it is automatically the LCM of this problem.
7 x m = 7m2 x 7 x m = 14m
17
237288135.5932203
1400cm
1400cm
If you mean: -8m+14m-8 then the given expression can be simplified to 6m-8