The chance of throwing a six with one die is one in six. With a pair of dice it is one in six2 or one in 36.
if there is only 1 6 your chances r 1 to 6
(s + 6)(6s - 7)
13s - 2
76 and 1/2 of them.
4 6s = 4*6 = 24. As a fraction, this can be written as 24/1.
16
-40 = 8-6s -40 - 8 = 6s -48 = 6s 8 = s
25 of them with a remainder of 2
The answer, using the Binomial distribution is 100C5*(1/6)5*(5/6)95 = 0.000291 (approx).
4/6 = 2/3
8 if them with a remainder of 2
Assuming it is not a loaded die, the chances are 1 in 6.