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Q: What are the common factors of 4ab and 5ab?

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-1ab^2 + 5b + 8 Step-by-step explanation: 3a^2+9ab+5-4a^2-4ab+3 3a^2-4ab^2=-1ab^2 9ab-4ab=5ab 5+3=8 -1ab^2+5ab+8

6a2 + 5ab - 6b2 = 6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)*(3a - 2b)

The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors

Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).

I'm going to assume a few things... 1.) the 2s after a letter are 2 2.) this is addition, because it's easier for me and if you wanted another operation, you should have stated so. 2a2b+a2+5ab+3ab2+b2+2a2b+2ab 4ab+a2+5ab+3b2a+b2+4ab+2ab 15ab+3b2a+a2+b2

6a

The GCF of 5ab and 56b squared is b.

4ab

4ab

55/5ab + 4/5ab = 59/5ab

4ab * 3a = 12a2b -----------

7ab-5ab = 2

5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.

4ab

Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)

gcd of 5ab,28xy

2a*2b = 4ab

(-a-7b+5)4ab

(5ab)2 = 25a2b2 (provided a and b are elements of a commutative group).

a^2b^2(4ab) = 8a^3b^3.

(5ab^2 + 4cd)(5ab^2 4cd) <

(4ab^2 + 3cd)(4ab^2 - 3cd)

6a2 + 5ab - 6b2 = (3a - 2b)(2a + 3b)

2a(2b) Would Give You The Answer 4ab. 2x2 = 4 And a x b = ab.

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