Considering the minus sign between 5ab and 6b2 then we have the polynomial as 6a2 + 5ab - 6b2. The polynomial is a quadratic polynomial.Steps to factorize a quadratic polynomial:1 - Multiply first term by third term. 6a2 x (-6b2) = -36a2b22 - If possible break the second term into two terms such that they multiple to -36a2b2. If not then it is factorized by Sridharacharya's formula.5ab can be broken as 9ab + (-4ab).These two terms multiply to give -36a2b2.So we can write 6a2 + 5ab - 6b2 = 6a2 + 9ab + (-4ab) - 6b2.6a2 + 9ab - 4ab - 6b2 = 3a(2a + 3b) - 2b(2a + 3b) = (2a + 3b)(3a - 2b).So the factors are (2a + 3b) and (3a - 2b).
-1ab^2 + 5b + 8 Step-by-step explanation: 3a^2+9ab+5-4a^2-4ab+3 3a^2-4ab^2=-1ab^2 9ab-4ab=5ab 5+3=8 -1ab^2+5ab+8
I'm going to assume a few things... 1.) the 2s after a letter are 2 2.) this is addition, because it's easier for me and if you wanted another operation, you should have stated so. 2a2b+a2+5ab+3ab2+b2+2a2b+2ab 4ab+a2+5ab+3b2a+b2+4ab+2ab 15ab+3b2a+a2+b2
The greatest common factor of 4ab and 6ab is 2ab. You simply take the greatest common factor from both factors. The greatest common factor of 4 and 6 is 2. The letters can be factored out because they appear in both factors
6a
The GCF of 5ab and 56b squared is b.
4ab
4ab
Assuming that non-leading numbers are exponents, the expression becomes12a^2b + 8a - 5a^2b + 2ab - 4ab^2 + 6ab - 2a - 3ab= 7a^2b + 6a + 5ab - 4ab^2= a*(7ab + 6 + 5b - 4b^2)
55/5ab + 4/5ab = 59/5ab
5a³ - 4ab + 2a³ = (5+2)a³ - 4ab = 7a³ - 4ab.
7ab-5ab = 2