Suppose the sides of the parallelogram are of lengths p and q and let p <= q.Then either 10 < p <= sqrt(120) and 120/p <= q < 12.5
or sqrt(120) <=p <= q <= 12.5
The area and perimeter of a parallelogram are not sufficient to determine its dimensions.
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
area of parallelogram= base*height perimeter= 2(length+breadth)
I don't know about the relation in the perimeters of a triangle and a parallelogram but if a triangle is on the same base on which the parallelogram is and the triangle is between the same parallel lines of the parallelogram, then the area of the triangle will be half the area of the parallelogram. That is, area of a triangle = 1/2 area of a parallelogram if the triangle is on the same base and between the same parallel lines.
area 63 and perimeter is 32
The area of a parallelogram does not provide enough information to determine its dimensions.
what are the dimensions of the rectangle with this perimeter and an area of 8000 square meters
The answer depends entirely on how the dimensions change. It is possible to change the dimensions without changing the perimeter. It is also possible to change the dimensions without changing the area. (And it is possible to change the area without changing the perimeter.)
Area = length of a side * vertical distance between that side and the side parallel to it. Perimeter = sum of the length s of all four sides.
Nothing at all.
Area is quadrupled (*4) and perimeter is doubled.
area is length times width