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Q: What are the dimensions of a rectangle whose diagonal is 25 inches and has an area of 300 square inches?

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Missing information. The rectangle could be a square then the two sides would be the square root of 5000 or about 70.71. As the rectangle gets longer the sides change and thus the dimensions.

The square of the diagonal is (652+692)=8986 The diagonal is then the square root of 8986=94.79...

12 square feet.

Without the dimensions, we won't be able to tell. The area of a rectangle is the length times the width. If those dimensions are in inches, the area will be in square inches.

The diagonal of a rectangle is the third and longest side of a triangle with sides the same as those of the rectangle, so its length is the square root of the sum of the squares of the lengths of the sides of the triangle, (Pythoagoras' Theorem) which are also the sides of the rectangle. If the rectangle is 3 inches by 4 inches, then the diagonal is the square root of 3 squared (= 9) and 4 squared (= 16) so the diagonal is the square root of 16 + 9 = 25, giving it the length of 5 inches.

4 x 10

You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com

There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13

Its dimensions are 6 inches by 7 inches because 2(6+7)=26 inches and 6*7=42 square inches

4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula

The area of Joseph’s rectangular homework desk is 1,008 square inches. If the length of his desk is 42 inches, how wide is his desk?

Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet

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