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There are four possibilities depending on the missing operational signs:

4y2 + 2y + 6 factors to 2(2y2 + y + 3)

4y2 + 2y - 6 factors to 2(y - 1)(2y + 3)

4y2 - 2y - 6 factors to 2(y - 1)(2y - 3)

4y2 - 2y + 6 factors to 2(2y2 - y + 3)

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Q: What are the factors for 4ysquared 2y 6?
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How do you solve the simultanious equation 4x plus 2y equals 12 x plus 2y equals 6?

If the two equations are (i) 4x + 2y = 12 and (ii) x + 2y = 6, proceed as follows: Rewrite (ii) as x = 6 - 2y; substitute this expression for x into (i) to result in 4(6 - 2y) + 2y = 12, or 24 - 8 y + 2y = 12, or - 6 y = 12 -24 = -12, or y = -12/-6 = 2. Then, back to (ii) again, x = 6 - 2(2) = 2.