35: 1, 5, 7, 35
36: 1, 2, 3, 4, 6, 9, 12, 18, 36
37: 1, 37
38: 1, 2, 19, 38
39: 1, 3, 13, 39
1, 3, 13, 39
1, 2, 4, 5, 8, 10, 20, 40
1, 41
1, 2, 3, 6, 7, 14, 21, 42
1, 43
1, 2, 4, 11, 22, 44
1, 3, 5, 9, 15, 45
26: 1, 2, 13, 26
34: 1, 2, 17, 34
35: 1, 5, 7, 35
38: 1, 2, 19, 38
45: 1, 3, 5, 9, 15, 45
I'll do the first three.
1, 2, 3, 5, 6, 10, 15, 30
1, 31
1, 3, 11, 33
Your turn.
1,3,13,39. 39 is composite #.
The factors of 39 are: 1, 3, 13, and 39.The prime factors of 39 are: 3 and 13.The factors of 50 are: 1, 2, 5, 10, 25, and 50.The prime factors of 50 are: 2 and 5.
As a product of its prime factors: 5*11*41 = 2255
The factors of 18 are: 1, 2, 3, 6, 9, 18The factors of 41 are: 1, 41
factors: 1, 7, 23, 161prime factors: 7, 23
Factors multiply. 1 and 41 are the only ones that make 41.
you cannot anser with 40, it is 39
31, 37, and 41 are prime. All others are composite, i.e., one of their factors is a smaller number.
If you are talking about 40 dollars, the answer is 40. It can't be 39 or 41.
The numbers are 39, 40 and 41.
41, 43 and 47 are the prime factors between 40 and 50
39
24 84 40 41 39
(x-1) (x+1) = x2 - 1. So 39 (= 40-1) times 41 (= 40+1) is 402 - 1 = 1600-1 = 1599. THE ANSWER ESTIMATED IS 1,600
1 and 41
1 and 41
The consecutive integers are 39, 40, and 41. To solve this algebraically, note that consecutive numbers can be indicated by the variables x, x+1, and x+2. For the sum x + (x+1) + (x+2) = 120, 3x +3 = 120 3x= 117 x= 39, followed by 40 and 41 39+40+41 = 120
41 is prime, therefore the factors are 1 and 41. Prime numbers don't have "proper" factors.