So if we call the first term of the sequence A,and the common difference d, then the formula for the nth term is A+ [(n-1)d] this just comes from understanding that the first term is A the second term is A+d the third is A+2d the 4th is A+ 3d so the nth term is A + (n-1)d. So let's set up two equations and solve them for A and d and then we are done A+ 8d=90 A+15d=153 This is the same as -A-8d=-90 A+15d=153 and we add these two equation to eliminate A. This is called elimination. You can also solve this system of 2 equations in 2 unknowns with substitution by substituting A=90-8d into the second equation. I think this is harder We have 7d=63 so d=9 and then plug that into either equation and A=18 So the first 4 terms are 18, 18+9, 18+18, 18+27 or we write 18, 27, 36, 45
The 9th term of the Fibonacci Sequence is 34Fibonacci Sequence up to the 15th term:1123581321345589144233377610
The 9th number in the Fibonacci Sequence is 34, and the 10th number in the Fibonacci sequence is 89.
A(n) = A(0) + (n-1)d Here we want A(9), A(0) = 19, d = 3.4 Therefore A(9) = 19 + (9-1)(3.4) = 19 + 8(3.4) = 19 +27.2 = 46.2
1/3
Each number is found by dividing the previous number by 3. The next number would be a fraction called "one third", and then "one ninth" and so on.
It is 25/144.
5
The 9th term of the Fibonacci Sequence is 34Fibonacci Sequence up to the 15th term:1123581321345589144233377610
The 9th number in the Fibonacci Sequence is 34, and the 10th number in the Fibonacci sequence is 89.
It is the number 9.
If you're multiplying, it's a to the sixteenth. If you're dividing, it's a to the second.
31
801AD was the first year of the ninth century.
A(n) = A(0) + (n-1)d Here we want A(9), A(0) = 19, d = 3.4 Therefore A(9) = 19 + (9-1)(3.4) = 19 + 8(3.4) = 19 +27.2 = 46.2
For 1/4, 1/9 and 1/16 the LCD is 144.
N (First, Second, Third, Fourth, Fifth, Sixth, Seventh, Eighth, Ninth)
Sheryl Searcy Ninth Grade Center's motto is 'Where Ninth Comes First!'.