Q: What are the first 6 even positive integers?

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First six even positive integers.

The sum of the first three even positive integers is 2 + 4 + 6 = 12.

They are 6 times 8 = 48

6 positive integers. 0,1,2,3,4 & 5

48 = 6 x 8, so the smaller is 6.

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First six even positive integers.

The sum of the first three even positive integers is 2 + 4 + 6 = 12.

2 + 4 + 6 + ... + 1816 + 1818 + 1820 = 829010

2, 4, 6, 8, ... continue adding 2 at a time, up to 2000.

They are 6 times 8 = 48

Many people would consider 0 to be the first even positive integer, however similar to the neutron in an atom, 0 holds a neutral position. Meaning it is neither a proton (+1) or electron (-1). So our first positive even integer would be 2.2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110, which is the sum of the first ten evenly positive integers.

Positive integers are 1, 2, 3, 4, 5, 6 ....

6 positive integers. 0,1,2,3,4 & 5

The sum of the first ten positive integers, i.e. 1,2,3,4,5,6,7,8,9, and 10, is 55. The sum of the first ten negative integers, i.e. -1,-2,-3,-4,-5,-6,-7,-8,-9, and -10 is -55. The sum of the first ten positive integers plus the sum of the first ten negative integers is 0.

The sum of the first n positive integers (i.e. 1+2+3+...+n) is given by n(n+1)/2 so the sum of the first 25 positive integers is 1+2+3+...+25 = 25x26/2 = 325. The sum of the first 25 EVEN numbers will be double this i.e. 2+4+6+...+50 = 650.

The positive even integers are: 0 2 4 6 and 8

48 = 6 x 8, so the smaller is 6.