Q: Three consecutive number whose sum is 126?

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41+42+43 = 126

41, 42 and 43

30, 31, 32 and 33

41, 42, 43

There is no solution. Since 126 is even and two consecutive integers have to be one odd and one even number, an odd and an even number cannot summate to an even number.

The two even consecutive integers are: 62+64 = 126

41, 42 and 43

41+42+43=126.

125, 126 and 127.

63+83=126.... hope it helps!

There are two consecutive even numbers. The numbers are 62 and 64.

41,42,43

The integers are 41, 42 and 43. Also, using consecutive even integers, you find: 40, 42 and 44.

Divide 126 by 2 and choose the even numbers on both sides.

The integers are are 41, 42 and 43.

124 + 125 + 126 = 375

The numbers are 40, 42 and 44.

126, 127, 128

They are 41, 42 and 43.

The numbers are 41, 42 and 43.

The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.The 13 consecutive numbers from 114 to 126 are composite.

124+125+126=375

The numbers are 62 and 64 are two consecutive integers that equal 126.

Let the consecutive multiples of 7 be 7x and 7(x+1).7x + 7(x+1) = 1267x + 7x + 7 = 12614x + 7 + 12614x = 126 - 714x = 119x = 119/14x = 8.5For 7x to be a multiple of 7, x must be a whole number, so there are no such consecutive multiples.

There are two consecutive even numbers. The numbers are 62 and 64.

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