answersLogoWhite

0


Best Answer

6

User Avatar

Kiera Lakin

Lvl 10
3y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

10y ago

Evaluate the expression Un = 3n - 3 for n = 1, 2, 3, 4, 5.

For n = 1 you get 3*1 - 3 = 3 - 3 = 0

For n = 2 you get 3*2 - 3 = 6 - 3 = 3

and so on.

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What are the first five terms of the sequence 3n-3?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What number comes next in the sequence 32-55-165-1848?

6590. One possible sequence is 2472/3N3 - 14421/2N2 + 26165/6N - 1390


What is two-thirds the cube of a number?

2/3n3


What is two-third of the cube of a number?

2/3n3


What is the GCF of 6n to the third power and 9n to the third power?

The GCF is 3n3


What is the next term in this sequence 7 12 30 70 141 252?

Given any number, it is always possible to find a polynomial of degree 6 that will fit the above numbers and the additional given number.The simplest position to value rule, in polynomial form, for the above sequence isUn = (3n3 - 5n2 + 4n - 12)/2 for n = 1, 2, 3, ...and accordingly, U7 = 412.


What is the pattern in one eighth two sevenths one half and four fifths?

One possible answer is: Un = (3n3 - 3n2 + 78n - 8)/560 for n = 1, 2, 3, 4.


What is the next number in this pattern 3 12 35 63?

Given ANY number, it is easy to find a polynomial of order 4 such that if you use it as a position to value rule you get the four given numbers and your chosen one as the fifth. As a result, any number can be the next in the sequence. The simplest polynomial of order 3 for the above four numbers is: Un = (-3n3 + 32n2 - 57n + 34)/2 for n = 1, 2, 3, ... Accordingly, the next number is 87.


The product of four consective integers is one less than a perfect square?

Suppose the smallest of the integers is n. Then the product of the four consecutive integers is n*(n+1)*(n+2)*(n+3) =(n2+3n)(n2+3n+2) = n4+6n3+11n2+6n So product +1 = n4+6n3+11n2+6n+1 which can be factorised as follows: n4+3n3+n2 +3n3+9n2+3n + n2+3n+1 =[n2+3n+1]2 Thus, one more that the product of four consecutive integers is a perfect square.


What is the missing number in this sequence 1 13 33 53?

The answer depends on which number is missing. Even if the location of the gap is know, there are infinitely many possible solutions. The solutions listed below are polynomials of the lowest degree. First: 5 using the rule Un = (-4n3 + 48n2 - 128n + 99)/3 Second: 0 using the rule Un = (-7n3 + 84n2 - 209n + 138)/6 Third: 21.666 (recurring) using the rule Un = (3n3 - 23n2 + 84n - 61)/3 Fourth: 50 using the rule Un = (-11n3 + 90n2 - 121n + 48)/6 Fifth: 65 using the rule Un = (-4n3 + 36n2 - 44n + 15)/3


What is the next number in the series 6 3 8 12?

Any number of your choice. It is possible to find a quartic (order 4) polynomial that will fit the given 4 points and any other. There is only one cubic that will do the trick: Un = (-3n3 + 26n2 - 63n + 52)/2 for n = 1, 2, 3, ... and according to it U5 = 6.


What is the fourth difference sequence formula?

A solution for 4th difference sequence is:Formula: Tn = an4+ bn3+ cn2 + dn + e1st term = a + b + c + d + e1st difference = 15a + 7b + 3c + d2nd difference = 50a + 12b + 2c3rd difference = 60a + 6b4th difference = 24aExample:Tn (term number) = 1 2 3 4 5 6 7Sequence = 1 41 209 643 1529 3101 56411st difference = 40 168 434 886 1572 25402nd difference = 128 266 452 686 9683rd difference = 138 186 234 2824th difference = 48 48 48Step 1: 4th difference = 24a:24a = 48a = 2Step 2: 3rd difference = 60a + 6b:60(2) + 6b = 138b = 3Step 3: 2nd difference = 50a + 12b + 2c:50(2) + 12(3) + 2c = 128c = -4Step 4: 1st difference = 15a + 7b + 3c + d:15(2) + 7(3) + 3(-4) + d = 40d = 1Step 5: 1st 1st term = a + b + c + d + e:2 + 3 - 4 + 1 + e = 1e = -1Answer:Tn = 2n4+ 3n3- 4n2 + n - 1


What is bradleys free rider track code 3?

-f 4i -f 52 -12 5a,-q 52 -1e 5d -26 5k -35 5q -46 62 -59 69 -6l 6h -85 6n -9g 6n,-br 6m -cp 6i -dq 6f -eu 6f -g2 6h -he 6k -it 6n -kh 6r -lu 71 -nc 79 -or 7h -qc 7p -rt 83 -td 8e -ut 8q -10g 95 -124 9j -13q a2 -15h aj -178 b3 -191 bl -1ap c6 -1ci cn -1eb d8 -1g4 dp -1hu eb -1jn es -1lh fe -1nb fv -1p5 gh -1qv h2 -1sp hk -1uj i5 -20d in -227 j8 -241 jq -25r kb -27m kt,-9h 6n -a8 6o -b2 6m -br 6i,-27o kt -28j l7 -29g lf -2ae lo -2bh m2 -2cg me -2da mr -2eb n9 -2fh nq -2gq oi -2i4 pe -2j9 q5 -2kj qu -2m0 rq -2nf so -2ot TM -2qc ul -2rt vk -2tc 10l -2us 11m -30c 12n -31t 13p -33e 14r -350 15t -36i 170 -384 183 -39n 196 -3ba 1aa -3ct 1bd -3eg 1ch -3g4 1dl -3hn 1eo -3jb 1fs -3kv 1h0 -3mj 1i4 -3o7 1j8 -3pr 1kc -3rf 1lg -3t4 1mj -3uq 1nl -40g 1oo -427 1pp -43v 1qq -45n 1rq -47g 1sq -498 1tq -4b0 1uq -4cp 1vq -4eh 20q -4ga 21q -4i4 22p -4jt 23p -4ln 24p -4ng 25p -4pa 26p -4r3 27o -4st 28o -4um 29o -50g 2an -52a 2bn -543 2cn -55t 2dl -57n 2eg -59h 2f7 -5ba 2fs -5d3 2ge -5er 2gt -5gk 2hb,-5j8 2ih -5k1 2ik -5ku 2ip -5ls 2iv -5mq 2j4 -5no 2j8 -5on 2jc -5pj 2jd -5qi 2jc -5rj 2j8 -5ss 2j3 -5ua 2j4 -5vu 2je -61b 2jo -62q 2k4 -64b 2kh -65u 2l0 -67i 2lg -697 2m4 -6at 2mq -6ck 2ni -6eb 2ob -6g2 2p7 -6hr 2q4 -6jj 2r2 -6ld 2s2 -6n6 2t3 -6p0 2u4 -6qq 2v6 -6sl 307 -6uf 31a -70a 32c -725 33f -740 34j -75d 35e -76r 36a -788 375 -79l 381,-7be 39h -7c1 39v -7cn 3aa -7df 3al -7e8 3b1 -7f1 3bc -7fr 3bo -7gj 3c5 -7hd 3cg -7i7 3cr -7j4 3d7 -7k6 3dm -7lb 3e6 -7mm 3eo -7o8 3f9 -7pj 3fn -7r0 3g2 -7sf 3gc -7tv 3gm -7vh 3h2,-85c 3kb -861 3kl -86q 3kr -87m 3l3 -88g 3l9 -899 3le -8a2 3li -8au 3lm -8bs 3lr -8cp 3m1 -8do 3m8 -8et 3mf -8g5 3mn -8hj 3mu -8j5 3n7 -8kg 3ne -8lt 3nl -8nb 3nt -8or 3o4 -8qd 3oc -8rv 3ok -8ti 3os -8v6 3p4 -90r 3pc -92g 3pl -946 3pt,-99u 3ve -9am 3vi -9bf 3vm -9c5 3vq,-99p 3vg -9ae 3vh -9b5 3vl -9br 3vt##