the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
The sum of the first five prime numbers is 28. The sum of the cubes of the first three prime numbers is 160. The average of 28 and 160 is 94.
The sum of the first three prime numbers that end with a 9 (19,29,59) is 107
30 - 31 = -1
Just multiply the first three prime numbers together.
which three prime numbers have a sum of 59
The first three prime numbers are 2,3,5. The smallest number divisible by 2,3 and 5 is 30 (2*3*5).
There are an infinite number of them. 8 has three prime factors, 30 is the first with three distinct prime factors.
3, 5, and 7 are three prime numbers whose average is 5.
The LCM of any three distinct prime numbers is their product.
There are not three prime numbers that have the sum of 3. The smallest prime number is 2. If all three prime numbers were 2, the sum would 2 + 2 + 2 = 6, so that is the smallest number that is the sum of three prime numbers.
The question, "the" three odd prime numbers, is wrong. There are much more than three odd prime numbers - in fact, infinitely many. There are infinitely many prime numbers, and all except the number 2 are odd.
first three prime nmbers are 5,7,11 last three are 13,11,7
23, 29 & 31.
2 + 3 + 5 = 10
They are the first three odd prime numbers.
It is 30
The product of the first three prime numbers (2, 3, and 5) is 30.
An emirp number is a prime number which, when you reverse the digits, produces a different prime number. Therefore, there are no single-digit emirp numbers. The first three emirp numbers are: 13, 17, 31