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The are: 3 9 15 21 and 27
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∙ 9y ago
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Why aren't all odd numbers divisible by 3?
Because not all odd numbers are multiples of 3 - I have shown you below that this is the case and you can see some multiples of 3 are even and some are odd and you can also see that there are even and odd numbers BETWEEN the multiples of 3. 1 (odd) 2 (even) 1*3 =3 (odd) 4 (even) 5 (odd) 2*3 = 6 (even) 7 (odd) 8 (even) 3*3 = 9 (odd) 10 (even) 11 (odd) 4*3 = 12 (even)
What are multiples of 9 that are also multiples of 2?
Since the lowest common multiple of 9 and 2 is 18, all of the common multiples of 9 and 2 are multiples of 18. The first five are: 18, 36, 54, 72, 90 Since 9 is odd thean there are going to be odd numbers, which are not multiples of two.
What are 5 multiples of both 3 and 5?
Five multiples of 3 are... 3 6 9 12 15 ect. Five multiples of 5 are... 5 10 15 20 25 ect.
What is the remainder when the sum of all the odd multiples of five from 1 to 2007 is divided by ten?
The odd multiples of 5 end with 5.If there is an even number of odd multiples of 5, their sum ends in 0, meaning their remainder when divided by 10 is 0;If there is an odd number of odd multiples of 5, their sum ends in 5, meaning their remainder when divided by 10 is 5.By "odd multiples of 5 from 1 to 2007 " do you mean:the multiples 1, 3, 5, ..., 2007 of 5?1 = 2 x 1 - 1, 3= 2 x 2 - 1, ..., 2007 = 2 x 1004 - 1 So there are 1004 multiples of 5, which is even so their sum has a remainder of 0 when divided by 10.the numbers between 1 and 2007 which are odd multiples of 5?1 ÷ 5 = 0.2 → first multiple of 5 in the range is 1 x 5 → the first odd multiple = 1 x 5 2007 ÷ 5 = 401.4 → last multiple of 5 in the range is 401 x 5 → the last odd multiple = 201 x 5401 = 2 x 201 - 1 which means there are 201 multiples of 5, which is odd so their sum has a remainder of 5 when divided by 10.As our number system is based on 10, the remainder when dividing by 10 gives the value of the units (last) digit of the original number.All even multiples of 5 end have a units digit of zero and do not affect the units digit of the sum when added; so the question could have included the even multiples of 5 (ie "What is the remainder when the multiples of five...") without changing the final answer.
Is every multiple of 3 an odd number?
No, 6, 12, 18, 24...are even numbers that are multiples of 3.
Are all multiples of 3 odd?
No - alternate multiples of 3 are odd, and alternate multiples are even.
Are all odd number divisible by 5?
No. Only odd numbers that are multiples of five.
Why are all multiples of 3 odd and even?
The multiples of all odd numbers are odd and even. Odd x odd = odd. Odd x even = even. Since odd and even numbers alternate, the multiples will alternate as well.
What are the common multiples of 3 7 but not 6?
Odd multiples of 21.
What are some odd multiples of five?
Any number ending in 5.
Why aren't all odd numbers divisible by 3?
Because not all odd numbers are multiples of 3 - I have shown you below that this is the case and you can see some multiples of 3 are even and some are odd and you can also see that there are even and odd numbers BETWEEN the multiples of 3. 1 (odd) 2 (even) 1*3 =3 (odd) 4 (even) 5 (odd) 2*3 = 6 (even) 7 (odd) 8 (even) 3*3 = 9 (odd) 10 (even) 11 (odd) 4*3 = 12 (even)
Are multiples of 3 odd?
No, some of them are, some are not.
Why does five have even and odd multiples?
That happens because 5 is an odd number. An odd number times an odd number will give you an odd product; an odd number times an even number will give you an even product. The same happens for the multiples of any other odd number.
Are the multiples of an odd number always odd?
No, only every other multiple is odd. Example: 3,6,9,12,15,18
Odd numbers with a multiple of 3 and not a factor of 8?
All odd multiples of 3 are not factors of 8.
Is all multiples of 3 odd?
No way. 3*10 is 30.
Are the multiples of 3 always odd?
No, 6 is a multiple of 3.
