Q: What are the integers if The sum of two integers is -1 the product of these integers is -56?

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7 and 8?

7 and 8

8 and 7.

-27+-29= -56

Your answers are 7 & 8 7 + 8 = 15 7 x 8 = 56

The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56

The numbers are 56 and 58.

They are are 7 and 8.

-56 and -1 -56+(-1)=-57 -56*(-1)=56

27 29

7 and 8

It depends on whether you mean sum or product or something else; whether the numbers are integers, rationals or reals; whether they are same or different, etc. 1,1,1 and 53 sum to 56. 1,1,1 and 56 multiply to 56.

The average of the two odd integers is 28. Therefore the two integers are 28-1 and 28+1, i.e 27 and 29.

35, 21

The numbers are 4 and 14

The two numbers are either 7 and 8 or -7 and -8.

The equation for this problem would be x + (x + 2) = 56.After combining the two x's, we get 2x + 2 = 56, then 2x = 54, which brings us to find that x = 27. So, 27 is the first odd integer. Since it is two consecutive odd integers, we need to add 2 to 27, giving us 29. Thus, the two consecutive odd integers whose sum is 56 are 27 and 29.

4,6,8,10

This would be impossible - since the mean of the three integers would have to be an integer, and if you divide -56 by 3, you do not get an integer.

27 + 29 = 56.

86

4 and 14 4 * 14 = 56 4 + 14 = 18

1 and -57

-7 multiplied by -8 = 56

Sum of first n integers is n/2 times n + 1 ie 27.5 x 56 which is 1540