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The multiples of 6 must total 270 ÷ 6 = 45

Let the smallest of the 5 consecutive numbers be n

Then n + (n + 1) + (n + 2) + (n + 3) + (n + 4) = 45

5n + 10 = 45 : 5n = 45 - 10 = 35

n = 35/5 = 7

The numbers are 7,8,9,10, 11

The multiples of 6 are thus 42, 48, 54, 60 & 66 and their total = 270.

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13y ago
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14y ago

Multiples are numbers that are evenly divisible by the original number (270). So, 540, 810, and so on.

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10y ago

1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 90, 135 and 270.

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7y ago

270, 540, 810, 1080, 1350, 1620, 1890 . . .

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8y ago

7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98 and just keep adding 7 until you get to 266.

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Q: What are the multiples of 270?
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