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Q: What are the multiples of 7 and is greater than 200?

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Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.

Consecutive numbers wouldn't both be multiples of 7. If you mean consecutive multiples of 7, the LCM of 210 and 217 is 6510 which is their product divided by 7.

Multiples of any number greater than one are composite.

7, 14, 21, 28, 35

7, 14, 21, 28, 35

7,14,21,28,35,42,49,56,63,70,77,84,91,98,105,112,119,126,133,140,147,154,161,168,175,182,189,196

84, 91, 98, 105, 112.

133,140,147,154,161,170,177,184,191 (200)

4,8,12,16,20

49, 56, 63, 70, 77, 84

Smallest multiple of 7 greater than 100 is 15 Largest multiple of 7 less than 1000 is 142 So number of multiples of 7 = 142 - 15 + 1 = 128

70

42 and its next three multiples.

... 7 x 30 = 210, that should give you a clue...

-7 is not greater than 7.

The first action sequence in the flow chart is to remove all multiples of 2 from numbers greater than 2. The next sequence removes removes all multiples of 3 from all numbers greater than 3. The third sequence removes all multiples of 5 from the remaining numbers greater than 5. The fourth sequence removes all multiples of 7 from the remaining numbers greater than 7. Additional sequences are added as needed to remove multiples of as many primes as desired in ascending order.

28-81 is greater

They are members of the set of numbers of the form 7*k where k is a positive integer less than 29.

15

203, 210, 217, 224, 231, 238, 245, 252, 259, 266, 273, 280, 287, 294, 301, 308, 315, 322, . . .

14

3

700 and 1400 have an LCM of 700.

The LCM of 210 and 211 is 44310, which is a multiple of 7.

int num = 0; int sum = 0; // 105 is the first integer greater than 100 which is evenly divisible by 7 for(int i = 104; i < 200; i+=7) {++num;sum += i; }