The first 12 multiples of 8 are 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88 and 96.
Infinity.
But 18 has 6 factors and they are 1, 2, 3, 6, 9 and 18 itself.
Multiples of 18 include 18, 36 and 54. For them to be common, they need to be compared to another set of multiples.
18, 36, 54, 72, 90, 108, 126, 144, 162, 180, 198, 216, 234, 252, 270, . . .
You need at least two numbers to find something in common, but I'll save you the trouble. The greatest common multiple of any set of numbers is infinite.
18, 36, 54, 72, 90, 108, 126, 144, 162, 180 . . .
324
1 x 18, 2 x 9, 3 x 6.
9 x 20 = 180
180 - 9 - 9 = 162
1 x 18 2 x 9 3 x 6 2 x 3 x 3
The factors for 18 are: 1,2,3,6,and 9
GCF(18, 27) = 9so, 18 + 27 = 9*2 + 9*3 = 9*(2 + 3) = 9*5 = 45.
4 x 9, 6 x 6 , 12 x 3, 36 x 1 all make 36.
All the factor strings are 2 x 9 3 x 6 2 x 3 x 3
X/9 = 18 multiply through by 9 X = 162 check 162/9 = 18 18 = 18 checks
18 = 1 x 18, 2 x 9, 3 x 6, 6 x 3, 9 x 2, 18 x 1
|x+9|=18 either x+9=18 or x+9=-18 so x=9 or x=-27 When |a|=b then a=b or a=-b
18 ÷ 9 x 2 = (18 ÷ 9) x 2 = 2 x 2 = 4
9 x 9 = 18 is false do you mean 9x + 9 = 18? then x =1
Well whats x. if x=19, then you do 19-1 ____ 9 19-1=18 18 __ = 18/9= 18 divided by 9 = 2. 9 it all depends on x
18 = 1 x 18, 2 x 9, 3 x 6, 6 x 3, 9 x 2, 18 x 1.
7/9 x 18 = 147/9 of 18 is 14.
18 = 1 x 18, 2 x 9, 3 x 6, 6 x 3, 9 x 2, 18 x 1.
1, 2, 3, 6, 9, 18: (1 x 18, 2 x 9, 3 x 6, 6 x 3, 9 x 2, 18 x 1)
Suppose x is the smaller number then x+9 is the larger. Then x*(x+9)= 162 or x2 + 9x - 162 = 0 or (x-9)*(x+18) = 0 So: x = 9 giving the solution 9 and 18 OR x = -18, giving the solution -18 and -9
(x^18 - 6x^9 + 18)(x^18 + 6x^9 + 18)