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If: y = 4x^2 -2x -1 and y = -2x^2 +3x +5

Then: 4x^2-2x-1 = -2x^2+3x+5 =>6x^2-5x-6 = 0

Solving the above quadratic equation: x = -2/3 or x = 3/2

Therefore by substitution the points of intersection are: (-2/3, 19/9) and (3/2, 5)

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Q: What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work with answers?
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What are the points of intersection of the parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5 showing work and answers?

If: y = 4x^2 -2x -1 and y = -2x^2+3x+5 Then: 4x^2 -2x -1 = -2x^2+3x+5 => 6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore the points of intersection by substitution are: (-2/3, 19/9) and (3/2, 5)


What are the points of intersection of the parabolas y equals 4x squared -2x -1 and -2x squared plus 3x plus 5 showing key stages of work?

If: y = 4x2-2x-1 and y = -2x2+3x+5 Then: 4x2-2x-1 = -2x2+3x+5 So: 6x2-5x-6 = 0 Solving the quadratic equation: x = -2/3 or x = 3/2 Points of intersection by substitution: (-2/3, 19/9) and (3/2, 5)


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If: y = 4x^2 -2x -1 and y = -2x^2 +3x +5 Then: 4x^2 -2x -1 = -2x^2 +3x +5 => 6x^2 -5x -6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore by substitution the points of intersection are: (-2/3, 19/9) and (3/2, 5)


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If: y = -2x^2 +3x +5 and y = 4x^2 -2x -1 Then: 4x^2 -2x -1 = -2x^2 +3x +5 So it follows: 6x^2 -5x -6 = 0 Using the quadratic equation formula: x = -2/3 or x = 3/2 Therefore points of intersection by substitution are at: (-2/3, 19/9) and (3/2, 5)

Related questions

What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?

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If: y = 4x^2 -2x -1 and y = -2x^2+3x+5 Then: 4x^2 -2x -1 = -2x^2+3x+5 => 6x^2-5x-6 = 0 Solving the above quadratic equation: x = -2/3 or x = 3/2 Therefore the points of intersection by substitution are: (-2/3, 19/9) and (3/2, 5)


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