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If: y = x^2 -2x +4 and y = 2x^2 -4x +4

Then: 2x^2 -4x +4 = x^2 -2x +4

Transposing terms: x^2 -2x = 0

Factorizing: (x-2)(x+0) => x = 2 or x = 0

Therefore by substitution points of intersect are at: (2, 4) and (0, 4)

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โˆ™ 2016-10-27 11:29:36
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Q: What are the points of intersection of the parabolas y equals x squared -2x plus 4 and y equals 2x squared -4x plus 4?
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