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Q: What are the prime fators of 28?

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they are 1,2,4,7,14,28

6 28

2 and 5

2 and 5.

2 and 19

Just 2

2 and 5

2 and 3

The prime factors of 66 are: 2, 3 and 11

As a product of its prime factors in exponents: 22*32 = 36

no its fators are 159 16 1 2544

The factors of 14 are 1,7,14 The factors of 28 are 1,2,14,28 The factors of 14 and 28 are 1,14

The only prime factor of 25 is 5.

1,050 = 2*3*5*5*7

They are itself and one because 13 is a prime number

1,2,3,6,13,26,39,78 Prime Factorization= 2*3*13

2 x 2 x 3 x 5 = 60

The factors of 49 are: 1 7 49 The prime factors are: 7 x 7

prime number if it only has less than 2 factors

56 divided by 2 = 28 28 divided by 2 = 14 14 divided by 2 = 7 7 cannot be divided by 3, or by 5 7 divided by 7 = 1 Therefore the prime factors of 56 are 2, 2, 2 and 7.

The answer depends on what is meant by "fators".

1,024 has only one prime factor . . . . . it's 2.( 210 =1024)

The prime factors of 243 are 3 * 3 * 3 * 3 * 3 So 243 = 3^5

prime factors of 28= 2,7

It can be. 28 is relatively prime to 33.