Equations: 3x-5y = 16 and xy = 7
Solutions: (7, 1) and (-5/3, -21/5)
The solutions are (-1.66..., -4.2) and (7, 1).
One.
They are simultaneous equations and their solutions are x = 41 and y = -58
one
If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1
3x = 96 - 75 produces the equations 3x = 21 and x = 7
If: 3x-5y = 16 then -5y = 16-3x => y = -3.2+0.6x by dividing all terme by -5 If: xy = 7 then x(-3.2+0.6x) = 7 => -3.2x+0.6x2 -7 = 0 Solving the quadratic equation: x = 7 or x = -5/3 Solutions of the equations by substitution are: x = 7, y = 1 and x = -5/3, y = -21/5
Through a process of elimination and substitution the solutions are s = 8 and x = 5
One.
They are simultaneous equations and their solutions are x = 41 and y = -58
Each of the two equations has an infinite number. Simultaneously, they have only one.
one
If: -x-3y = -4 and 3x+5y = 16 Then: x = 7 and y = -1
Not until it equals something. Equations have equals signs.
the system of equations 3x-6y=20 and 2x-4y =3 is?Well its inconsistent.
3x = 96 - 75 produces the equations 3x = 21 and x = 7
If "equations-" is intended to be "equations", the answer is y = -2. If the first equation is meant to start with -3x, the answer is y = 0.2
Simultaneous equations.