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What are the solutions to the simultaneous equations of x over 3 -y over 4 equals 0 and x over 2 plus 3y over 10 equals 27 over 5?
Wiki User
∙ 7y ago
Simultaneous equations: x/3 -y/4 = 0 and x/2 +3y/10 = 27/5
Multiply all terms in the 1st by 12 and in the 2nd equation by 10
So: 4x -3y = 0 and 5x +3y = 54
Add both equations together: 9x = 54 => x = 6
Solutions by substitution: x = 6 and y = 8
Wiki User
∙ 7y ago
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x/3-y/4 = 0 => multiply all terms by 12 => 4x-3y = 0 x/2+3y/10 = 27/5 => multiply all terms by 10 => 5x+3y = 54 4x-3y = 0 5x+3y = 54 Add both equations together which will eliminate 3y: 9x = 54 Divide both sides by 9: x = 6 Substituting the value of x into 5x+3y = 54 and 4x-3y = 0 gives y a value of 8. Therefore: x = 6 and y = 8
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