0
y2 + 4y -12 = 0
y2 + 6y - 2y -12 = 0
y(y + 6) -2(y +6) = 0
(y -2) x (y + 6) = 0
Hence (y-2) is zero which gives y = 2
or (y + 6) is zero which gives y = -6
The roots or solutions to the equation y2 + 4y -12 = 0 are y = 2 and y = -6
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