I'm taking an awesome chemistry final tomorrow. So, I'm not a massive failure at this:
k=mol/liters
Kc can only determine by experiment , not by evaluations of equations. so when writting the eq of Kc= [] products /[reactants], do not use units for [], as Kc has no units. Kc, only affected by temperature...
The formula is F = kx, so solving for "k", you get k = F/x; in other words, a force divided by a distance. In SI units, you would use newtons / meter.
Nm-1.
The value of the equilibrium constant K is only influenced by temperature.
It will take a short time to reach equilibrium It will take a long time to reach equilibrium The equilibrium lies to the right The equilibrium lies to the left Two of these One of those answers...
Values of general gas constant are: (value dependant on units) R = 0.08205746 [atm. ℓ.mol-1.K-1] R = 8.314472 [Pa.m3.mol-1.K-1 or J.mol-1.K-1] R = 1.99 [Cal.mol-1.K-1]
R = 0.082 ATM L/mol K
Kc is the equilibrium constant.
K is the equilibrium constant, Q is a concentration.
Kc is the equilibrium constant and is the ratio of the activity of the reactants (numerator) to the activity of the product (denominator). The activity of each component is raised to the power of its corresponding chemical stoichiometric coefficient. Since the activity of each chemical is unitless, the equilibrium constant will also have no units. Example: For equilibrium of chemicals in the gas phase, each activity will be measured by its partial pressure (units of pressure) multiplied by its fugacity (units of 1/pressure), so the activity of each gas participating in the equilibrium will be unitless, and the corresponding ratio (Kc) will be unitless.
Equal to one another. K= k1/k-1 where k1 is the forward reaction, k-1 is the backwards reaction and K is the equilibrium constant.
NO!!! A large Equilibrium Constant means that nearly all the reactants have been used up to reach the equilibrium. Conversely a small K(eq) indicates that equilibrium is reached when very little of the reactants have been used.
The value of the equilibrium constant K is only influenced by temperature.
Mathematically, Hooke's law states that: F = -kx, Where, x is the displacement of the end of the spring from its equilibrium position (in SI units: "m"); F is the restoring force exerted by the material (in SI units: "N" or kgms-2); and k is the force constant (or spring constant) (in SI units: "N·m-1" or "kgs-2").    
Equilibrium constant changes when temperature changes. For an endothermic reaction, the equilibrium constant increases with temperature while for an exothermic reaction equilibrium constant decreases with increase in temperature. Equilibrium constants are only affected by change in temperature.
eqb constant k For a general EQN A+B=S+T the equilibrium constant can be defined by[1] k={S}{T}/{A}{B} {S} = MOLAR CONC. OF S{T} = MOLAR CONC. OF T{A} = MOLAR CONC. OF A{B} = MOLAR CONC. OF B
It will take a short time to reach equilibrium It will take a long time to reach equilibrium The equilibrium lies to the right The equilibrium lies to the left Two of these One of those answers...
L •atm/mole•k
L •atm/mole•k
The extension of a spring is in direct proportion with the load added to it as long as this load does not exceed the elastic limit.F = -kxwhereF is the restoring force exerted by the material (in SI units: N);x is the displacement of the end of the spring from its equilibrium position (in SI units: m);k is the force constant (or spring constant) (in SI units: N·m-1 or kgs-2).