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What are the values of b and c when y plus 4x equals 11 is the perpendicular bisector line of the line joining b 2 to 6 c on the Cartesian plane?
Wiki User
∙ 10y ago
If the points are (b, 2) and (6, c) then to satisfy the straight line equations it works out that b = -2 and c = 4 which means that the points are (-2, 2) and (6, 4)
Wiki User
∙ 10y ago
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Line be is the bisector of segment ac if ab equals 7 ac equals?
14
If a circle with its centre at the origin has a chord with slope m the equation of the right bisector of the chord is y equals mx is this statement true or false?
False. 1). The proposed equation y=mx suggests that the chord's right bisector has no y-intercept, i.e. passes through the origin. This is interesting, and appears plausible, and I'm willing to acknowledge that this aspect of it is true. But ... 2). If the slope of the chord is 'm', then the slope of its right bisector is not also 'm'. If it were, that would make the chord and its bisector parallel, which would be pretty silly. The slope of any line perpendicular to the chord, including its right bisector, has to be '-1/m'. The equation of the chord's right bisector is: Y = -X/m .
What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
What is the perpendicular distance from the point 2 4 to the line y equals 2x plus 10 on the Cartesian plane?
Known equation: y = 2x+10 Perpendicular equation: 2y = -x+10 Both equations intersect at: (-2, 6) Distance from (2, 4) to (-2, 6) is sq rt of 20 using the distance formula
Ray mn is the bisector of segment kl kl equals km and km equals 5 cm find kn?
2.50 cm
What are the values of a and b when y plus 4x equals 11 is the perpendicular bisector of the line joining a 2 to 6 b showing workings?
They must be equidistant from the point of bisection which is their midpoint and works out that a = -2 and b = 4 Sketching the equations on the Cartesian plane will also help you in determining their values
What are the values of a and b given that y plus 4x equals 11 is the perpendicular bisector equation of the line joining a 2 to 6 b?
Their values work out as: a = -2 and b = 4
If yz is a perpendicular bisector of ax then yxz equals Yaz?
True. (Apex)
What is the perpendicular bisector equation of the line y equals 17 -3x that spans the parabola of y equals x squared plus 2x -7?
In its general form of a straight line equation the perpendicular bisector equation works out as:- x-3y+76 = 0
What is always perpendicular to -3x plus y equals 2?
The x and y axes on the Cartesian plane are perpendicular to each other at the point of origin
What are the values of p and q if y plus 4x equals 11 is the perpendicular bisector equation of the line joining p 2 to 6 q?
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
What is the perpendicular bisector equation of the chord y equals x plus 5 within the circle x2 plus 4x plus y2 -18y plus 59 equals 0?
Form a simultaneous equation with chord and circle and by solving it:- Chord makes contact with circle at: (-1, 4) and (3, 8) Midpoint of chord: (1, 6) Slope of chord: 1 Slope of perpendicular bisector: -1 Perpendicular bisector equation: y-6 = -(x-1) => y = -x+7
What is the value of k when y equals kx plus 14 is the perpendicular bisector equation of the line from 1 2 to 9 6?
Points: (1, 2) and (9, 6) Midpoint: (5, 4) Slope: 1/2 Perpendicular slope: -2 Perpendicular bisector equation: y-4 = -2(x-5) => y = -2x+14 Therefore: k = -2 thus satisfying the given bisector equation
What is the perpendicular bisector equation of the line y equals x plus 5 spanning the circle x2 plus 4x plus y2 -18y plus 59 equals 0?
Equation of line: y = x+5 Equation of circle: x^2 +4x +y^2 -18y +59 = 0 The line intersects the circle at: (-1, 4) and (3, 8) Midpoint of line (1, 6) Slope of line: 1 Perpendicular slope: -1 Perpendicular bisector equation: y-6 = -1(x-1) => y = -x+7 Perpendicular bisector equation in its general form: x+y-7 = 0
What are the possible values of a and b when the straight line of y equals ax plus 14 is the perpendicular bisector of the line joining the points 1 2 and b 6?
Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.
What value of k makes the line x equals 7 the perpendicular bisector of the segment with endpoints A 10 2 and B k 2?
As there is no change in y, the perpendicular bisector is given by x = (10 + k)/2 This is given as x = 7; thus: → (10 + k)/2 = 7 → 10 + k = 14 → k = 4
What are the values of t and v when y plus 4x equals 11 is the perpendicular bisector of the line joining t 2 and 6 v?
The slope of the line is 1/4 So the values are t = -2 and v = 4 Because they satisfy the equation: (v-2)/6-t = 2/8 = 1/4
