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What are the values of t and v when y plus 4x equals 11 is the perpendicular bisector of the line joining t 2 and 6 v?
Wiki User
∙ 12y ago
The slope of the line is 1/4
So the values are t = -2 and v = 4
Because they satisfy the equation: (v-2)/6-t = 2/8 = 1/4
Wiki User
∙ 12y ago
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What are the values of a and b given that y plus 4x equals 11 is the perpendicular bisector equation of the line joining a 2 to 6 b?
Their values work out as: a = -2 and b = 4
What are the values of p and q if y plus 4x equals 11 is the perpendicular bisector equation of the line joining p 2 to 6 q?
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
What are the possible values of a and b when the straight line of y equals ax plus 14 is the perpendicular bisector of the line joining the points 1 2 and b 6?
Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.
What are all the possible values of a and b given that y equals ax plus 14 is the perpendicular bisector of the line joining 1 2 to b 6?
Perpendicular equation: y = ax+14 Slope of line: 2-6/1-b = -1/a Multiply both sides by 1-b: -4 = -1+b/a By trial and improvement: -4 = -1+9/-2 By trial and improvement: -4 = -1-9/2.5 Therefore: a = -2 and b = 9 or a = 2.5 and b = -9
What are the vaues of a and b when the equation y plus 4x equals 11 is a perpendicular bisector to the line whose end points are at a 2 and 6 b on the Cartesian plane?
To satisfy the terms of the given equation the values of 'a' and 'b' are -2 and 4 respectively because:- End points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular equation: y-3 = -4(x-2) => y = -4x+11 or y+4 = 11
What are the values of a and b given that y plus 4x equals 11 is the perpendicular bisector equation of the line joining a 2 to 6 b?
Their values work out as: a = -2 and b = 4
What are the values of p and q if y plus 4x equals 11 is the perpendicular bisector equation of the line joining p 2 to 6 q?
The values of p and q work out as -2 and 4 respectively thus complying with the given conditions.
What are the values of a and b when y plus 4x equals 11 is the perpendicular bisector of the line joining a 2 to 6 b showing workings?
They must be equidistant from the point of bisection which is their midpoint and works out that a = -2 and b = 4 Sketching the equations on the Cartesian plane will also help you in determining their values
What are the possible values of a and b when the straight line of y equals ax plus 14 is the perpendicular bisector of the line joining the points 1 2 and b 6?
Possible values: a = -2 and b = 9 or a = 5/2 and b = -9 Drawing a sketch on graph paper with the information already given helps.
What are the values of b and c when y plus 4x equals 11 is the perpendicular bisector line of the line joining b 2 to 6 c on the Cartesian plane?
If the points are (b, 2) and (6, c) then to satisfy the straight line equations it works out that b = -2 and c = 4 which means that the points are (-2, 2) and (6, 4)
What are all the possible values of a and b given that y equals ax plus 14 is the perpendicular bisector of the line joining 1 2 to b 6?
Perpendicular equation: y = ax+14 Slope of line: 2-6/1-b = -1/a Multiply both sides by 1-b: -4 = -1+b/a By trial and improvement: -4 = -1+9/-2 By trial and improvement: -4 = -1-9/2.5 Therefore: a = -2 and b = 9 or a = 2.5 and b = -9
What are the vaues of a and b when the equation y plus 4x equals 11 is a perpendicular bisector to the line whose end points are at a 2 and 6 b on the Cartesian plane?
To satisfy the terms of the given equation the values of 'a' and 'b' are -2 and 4 respectively because:- End points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular equation: y-3 = -4(x-2) => y = -4x+11 or y+4 = 11
How do you work out the equation for the perpendicular bisector of the straight line joining h k and 3h -5k showing details of your work?
8
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