Equation: 6x^2 +2x +k = 0
Using the discriminant formula: k = 1/6
Using the quadratic equation formula: x = -1/6
Check: 6(-1/6)^2 +2(-1/6) +1/6 = 0
(x, y) = (-3, -3) or (3, 3)
Because the variables of x and a have different values so they can't be equal.
The value of such an expression depends on the values assigned to the variables, in this case, x and c.
Since the word 'equals' appears in your questions it might be what is called a trigonometric identity, in other words a statement about a relationship between various trigonometric values.
They intersect at points (-2/3, 19/9) and (3/2, 5) Solved by combining the two equations together to equal nought and then using the quadratic equation formula to find the values of x and substituting these values into the equations to find the values of y.
Using the discriminant the possible values of k are -9 or 9
Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.Substitute the values of the variables into the inequality. If the inequality is true then they are a solution, if not, they are not.
-2
You can represent values using variables. This can only be done with whole numbers.
To represent values
Yes, if you have two limiting variables with other possibles variables between them, the variables between the limiting variables would be continuous.
(52/11, 101/11) and (-2, -11) Rearrange 3x-y = 5 into y = 3x-5 and substitute this into the curve equation and then use the quadratic equation formula to find the values of x which leads to finding the values of y by substituting the values of x into y = 3x-5.