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What are the values of x y and z when 2x plus 3y plus 5z equals 1 and have a product of 1 over 27 showing work with explanations?
Wiki User
∙ 7y ago
If: 2x+3y+5z = 1
Then: 2(1/6)+3(1/9)+5(1/15) = 1 because 1/3+1/3+1/3 = 1
So it follows: 2(1/6)*3(1/9)*5(1/15) = 1/27 because 1/3*1/3*1/3 = 1/27
Therefore: x = 1/6, y = 1/9 and z = 1/15
Note that when given problems like the above simply let the sum of the terms be the numerators of three fractions and their denominators be three times the coefficient of the variables.
Wiki User
∙ 7y ago
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