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Q: What are the x-intercepts of x squared plus 24x plus 40?

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No solution in integers.

x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50

4x + 20

Factorise it: (x + 5)(3x - 8)

this equals 818

Related questions

(3x - 8)(8x + 5)

No solution in integers.

x - 2

1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.

x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50

2 squared plus 2 squared equals 16 because 2 squared is 4 times 4 equals 16. Math: 4x4=16 so your answer is 16 :)!

Factor out -2: -2(x squared +11x-20). This is fully factored.

4x + 20

No. it's not a prime number when x = 40, 41, 81,82 ...

Factorise it: (x + 5)(3x - 8)

'40 squared' simply means 40 times itself (40 x 40) which equals 1,600

You can find the value of x by equating the two equations.x^2+2x+40 = x^2-x +190Firstly, subtract x^2 from both sides2x+40 = -x + 190Now subtract 40 from each side2x = -x + 150Now add x to each side3x = 150Divide by 3x = 50