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I think you might mean f(x)+2? Or do you mean f(x+2)? Either way it depends on what f(x) is.
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∙ 13y ago
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What are the zeros of the polynomial function f(x) x(x plus 5)(x and ndash 8)?
They are x = 0, -5 and +8.
What are the zeros for this function?
The function is F(x)= x^3+3x^2-6x+20
If f(x)2x-1 and g(x) x plus 2 fimd (f plus g)(x)?
h(x)=3x-4
For f x 2x plus 1 and g x x2-7 find f g x?
f(x) = 2x + 1 g(x) = x^2 - 7 So f*g(x) = f(g(x)) = f(x^2 - 7) = 2*(x^2 - 7) + 1 = 2*x^2 - 14 + 1 = 2*x^2 - 13
What are the zeros of the function f(x) -4(x-3)(x 5)?
what is the sum of
What are the zeros of the function f of x equals 5x cubed minus x squared minus 18x plus 8?
-2, 1.74 and 0.46
X2 plus 11x plus 6 rational zeros?
x^2 + 11x + 6 has no rational zeros.
What are the zeros of the polynomial function f(x) x(x plus 5)(x and ndash 8)?
They are x = 0, -5 and +8.
Real zeros of x3 -13x plus 18?
f(2) = 8 - 26 + 18 = 0 (x-2) is a factor of f(x), x = 2 f(x) = (x-2)(x2 + 2x -9) x2 + 2x - 9 = 0 (x+1)2 - 10 = 0 x + 1 = +-sqrt10 x = -1 + sqrt10, -1 - sqrt10, 2
Is it always true that between any two zeros of the derivative of any polynomial there is a zero of the polynomial?
No. Consider the polynomial: f(x) = x3 + 4x2 + 4x + 16 then f'(x) = 3x2 + 8x + 4 = (3x + 2)(x + 2) => x = -2/3, -2 are the zeros of f'(x) Using the second derivative: f''(x) = 6x + 8 it can be seen that: f''(-2) = -4 -> x = -2 is a maximum f''(-2/3) = +4 -> x = -2/3 is a minimum But plugging back into the original polynomial: f(-2) = 16 f(-2/3) = 14 22/27 Between the zeros of the first derivative, the slope of the polynomial is negative so that the polynomial is always decreasing in value, but as the polynomial is greater than zero at the zeros of the first derivative, it cannot become zero between them. That is it has no zeros between the zeros of its first derivative f(x) = x3 + 4x2 + 4x + 16 = (x + 4)(x2 + 4) has only 1 zero at x = -4.
What are the zeros for this function?
The function is F(x)= x^3+3x^2-6x+20
What is the domain of the function f x x 2 plus 4?
The domain of the function f (x) = square root of (x - 2) plus 4 is Domain [2, ∞)
What function has a vertex at the origin f(x) (x plus 4)2 f(x) x(x and ndash 4) f(x) (x and ndash 4)(x plus 4) f(x) and ndashx2?
It is f(x) = -x2 or (-x)2, whichever you intended.
What are distinct zeros?
The zeros of f(x), a function of the variable x, are those values of x for which f(x) = 0. These are points at which the graph of f(x) crosses (or touches) the x-axis. Many functions will do so several times over the relevant domain and the values (of x) are the distinct zeros.
When f(x) is divided by x-1 and x plus 2 the remainders are 4 and -2 respectively. Hence find the remainder when f(x) is divided by x2 plus x-2?
The answer is indeterminate because the degree of f(x) is not specified.
What is f of x equals x squared plus 1?
F(x)=[x^2]+1
F(x) 3x plus 2 What is f(5)?
F(x) = 3x + 2 f(5) = 3*5 + 2 = 17
