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How many 4 digit numbers can be formed using a digit only once per number?
There are ten digits 0-9 that you can choose from. 10P4 = is the number of ways to order these ten digits into four digit numbers.However, 0 cannot begin the number or else it is a 3 digit number (0341 is a three digit number). So, we must subtract from 5040 the number of 3 digit numbers which do not contain 0. There are 1-9 digits to choose from. 9P3 = 504 is the number of ways to order these nine digits into three digit numbers.5040 - 504 = 4536______________________________________________Another way to arrive at the same result:You have 9 choices for the first number (1,2,3,...,9). Once you choose the first number you have 9 numbers to choose from for each of the remaining three numbers: (0,1,2,3,...9) but excluding the number you chose for the first number. So you have (9P3) ways to choose the final three digits.Thus, you have a total of 9*(9P3) ways to form your four digit number:9*(9P3)=9*9*8*7=4536
In how many ways can you write the number 3?
3 times... 3 three III
What are three ways to write the number 81 in exponents?
92, 34, or 81 * 100.
Can you use exponents to write the number 81 three different ways?
81 = 34 = 92 = 65610.5
How many ways are there to create a four digit number using 2789?
24 ways
What is the probability that a 3-digit positive integer picked at random will have one or more 7 in its digits?
A three digit number can be chosen in 9*10*10 = 900ways No. of ways to choose a three digit number without 7 is 8*9*9 = 648 ways probability of picking a three digit number that includes atleast one digit that is 7 is 1- (648/900) = 252/900 = 7/25
How many different ways can you make the number 10 write the number sentences?
There are three ways you can write the number 10. You can use X, as in Roman numerals, ten, or 10.
How many 4 digit numbers can be formed using a digit only once per number?
There are ten digits 0-9 that you can choose from. 10P4 = is the number of ways to order these ten digits into four digit numbers.However, 0 cannot begin the number or else it is a 3 digit number (0341 is a three digit number). So, we must subtract from 5040 the number of 3 digit numbers which do not contain 0. There are 1-9 digits to choose from. 9P3 = 504 is the number of ways to order these nine digits into three digit numbers.5040 - 504 = 4536______________________________________________Another way to arrive at the same result:You have 9 choices for the first number (1,2,3,...,9). Once you choose the first number you have 9 numbers to choose from for each of the remaining three numbers: (0,1,2,3,...9) but excluding the number you chose for the first number. So you have (9P3) ways to choose the final three digits.Thus, you have a total of 9*(9P3) ways to form your four digit number:9*(9P3)=9*9*8*7=4536
What are three ways to write the number 81 using exponents?
Three ways of writing 81 with exponents are: 92, 34, and 32 X 32.You could also write it as 8.1 x101.
In how many ways can you write the number 3?
3 times... 3 three III
What are three ways to write the number 81 in exponents?
92, 34, or 81 * 100.
How many three digit numbers can be formed such that the sum of the digits is 6?
21 ways assuming no leading zeros, that is the smallest possible number with three digits is 100 Otherwise if leading zeros are allowed, it is 28 ways. For three digit numbers the first digit can be 1-6. Leaving the remaining two digits to be 6-value_of_first_digit. For first digit 6, the remain two digits sum to 0 which means they can only be 00, ie the number 600 - 1 number For first digit 5, the remain two digits sum to 1 which means they can be 01 or 10, ie the numbers 501, 510 - 2 numbers For first digit 4, the remain two digits sum to 2 which means they can be 02. 11, 20, ie the numbers 402, 411, 420 - 3 numbers etc It can be seen that the number of ways of making a two digit number (with leading zeros) sum to a number less than 10 is the required sum plus 1. So for the remaining first digits, the number of ways are: 3 -> 4 ways, 2 -> 5 ways, 1 -> 6 ways. Thus the total number of ways is 1 + 2 + .. + 6 = 21 If leading zeros are permitted, so that, for example, 060 (60) and 006 (6) are considered as three digits numbers, then there are a further 7 ways with a first digit of 0, making a total 28 ways.
How many ways are there in which the digits 1 to 9 can be used to write a fraction equal to 12?
None. A fraction is a simple division. 2/4 is 2 divided by four. No one digit number can divide into twelve equally. Therefore, you cannot write a one-digit number to equal twelve.
How many ways are there to write a 3-digit positive integer using digits 1 3 5 7 and 9 if no digit is used more than once?
There are 5 choices for the first digit, as any of the 5 given digits can be used. After selecting the first digit, there are 4 remaining choices for the second digit, and 3 choices for the third digit. Therefore, the total number of ways to write a 3-digit positive integer using the given digits without repetition is 5 x 4 x 3 = 60 ways.
Can you use exponents to write the number 81 three different ways?
81 = 34 = 92 = 65610.5
How many ways are there to create a four digit number using 2789?
24 ways
How do you figure out how many times 5 digit numbers can be made by using the numbers 12345 without repeating a number twice?
The first digit can be any one of 1, 2, 3, 4 or 5. So you can choose the first digit in 5 ways. Having done that, you have only four unused digits. So you can chosse the second digit in 4 ways. Now then you have only three digits left so the third digit can be chaosen in 3 ways and so on. Total number of ways: 5*4*3*2*1 = 120
