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One way to find out is write a formula. Let N and N+1 be the two integers, then N(N+1) = 182 N^2 + N - 182 = 0 This is a quadratic equation. If the factors are not obvious, (N -13)(N + 14) , then use the quadratic formula to find N. The factors tell you there are two possible solutions for N; 13 and -14. Now add 1 to these to get the two consecutive integers. 13 & 14 will work and -14 & -13 will work.

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โˆ™ 2009-04-28 02:14:53
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Q: What are two consecutive integers have a product of 182?
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