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xy = 64

x + y = 16

y = 16-x

x(16-x) = 64

16x -x^2 -64 = 0

x^2 -16x + 64 = 0

(x-8)(x-8) =0

both factors = 8

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13y ago
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Q: What are two factors of 64 that have a sum of 16?
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