They are: 5 and 14
We will get two values of y . One is y=6 and another is y=13
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
19 & 17
The sum of two numbers witha difference of two equals forty can be set up and solved this way: x + (x - 2) = 40 2x - 2 = 40 2x = 42 x = 21 x - 2 = 19 The two numbers are 21 and 19.
The numbers are 19 and 5
If two numbers have a sum of 31 and a product of 228, then the two numbers are 12 and 19. Adding them will give you 31, and multiplying them gives you 228.
The two numbers are 19 and 7. 19 + 7 = 26, and 19 x 7 = 133.
16 and 3
6 and 13
67
441
19
1.61013 and 17.38987 (approx).
The two numbers are 6 and 13 so therefore the smaller number is 6
The numbers are: 6 and 19
13 + 6 = 19 19 + 6 = 25. 19 X 6 = 114.
If you meant "what two prime numbers have a sum of 36?" the answer is 19 and 17.