Let the number 'n' & 'n+1'
Hence their product is
n(n+1) = 1122
Multiply out the brackets
n^2 + n = 1122
n^2 +n -1122 = 0
It is now in Quadratic form either factor or use the Quadratic Eq'n.
n = [-1 +/- sqrt[(1)^2 - 4(1)(-1122)]} / 2(1)
n = -1 +/- sqrt[ 1 + 4488]} / 2
n = -1 +/- sqrt[4489] / 2
n = { -1 +/- 67}/ 2
n = -68/2 = -34
&
n = 66/2 = 33
Hence the two numbers are 33,34.
33X34=1122 34-33=1
3 and 84.
Consecutive numbers are whole numbers whose difference is 1.
-12
They are: 2 and 140
36
-76 and 76 whose product is -5776.
11
Not whole numbers, no.
7 & 21
1 and 0 are the two whole numbers with their sum same as their difference
Consecutive numbers are whole numbers whose difference is 1.
3 and 84.
-12
10 and 16.
10 and 28
50 and 30
They are: 2 and 140