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There is no celestial object at that distance.
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How many miles equal 24000 inches?
Well, there are twelve inches in each foot, so divide 24000 by 12. You have 2000 feet. One mile, is 5280 feet. So, you divide how many feet you have, by how many feet are required. So, 2000 feet / 5280 feet = 0.3787879 miles So, 24000 inches, = 0.3787879 miles. Sincerely, Onel4stkill
At 24000 miles per hour how long to travel to the sun?
The distance from Earth to the Sun is about 9.29 x 107 miles. You want to go 2.4 x 104 MPH? Just divide the two: 9.29 x 107 Miles ----------------- 2.4 x 104 Miles Per Hour The Miles cancel out and you're left with: 3,870 Hours 3,870 Hours ------------------ 24 Hours Per Day Answer: 161 Days
What must be the elevation of an observer in order that he may be able to see an object on the earth thirty miles away assuming earth's radius is 3956 mi and earth is smooth sphere?
You should really try to solve this yourself first, in order to maximize the value in doing that. If you read this solution, please understand each step before proceeding to the next step, otherwise the lesson will be lost to you. To determine the required elevation of an observer in order that he may be able to see an object on the earth thirty miles away, assuming the earth's radius is 3956 mi and the earth is a smooth sphere, first draw the triangle involved. This is a right triangle, where the hypotenuse is the radius of the earth plus the elevation of the observer. One side is the radius of the earth to the object. The other side is the line of sight distance from the observer to the object, which is greater than 30 miles. That line of sight is tangent to the earth's circumference, at the point of the object, so the angle of line of sight relative to the radius at the object is 90 degrees. The angle at the center of the earth is 360 degrees times 30 miles divided by the circumference of the earth, 2 pi 3956, or 24856, which is an angle of 0.4345 degrees. The hypotenuse of a right triangle with one angle of 0.4345 degrees and side of 3956 is 3956 divided by cosine 0.4345 degrees, or 3956.1138 miles. Subtract the radius, 3956 miles, and you get 0.1138 miles, or 601 feet. Not asked, but answered for completeness, is that the line of sight distance is hypotenuse times sine 0.4345 degrees, or 30.0005751 miles, or 3.04 feet more than 30 miles.
What is 3280.8399 feet in miles?
3,280.8399 feet = 0.621371193 miles
What is the speed of an object that travels 50 miles in 5 seconds?
10 miles/second!
Is the Earth closer to the Moon or Venus?
The moon, which is, by far, the closest celestial object to Earth. The moon varies between about 220,000 and 250,000 miles from Earth. Venus never comes closer than 24,000,000 miles.
How many meters are in 24000 miles?
There are 38624256 meters in 24000 miles. 24000 miles x 1609.344 meters/1 mile = 38624256 meters 1 miles = 1609.344 meters
How many miles is 24000 inches?
It is: 24000/36 = 666.67 yards and so 1760/666.67 = about 2.64 miles
Where is the earth going at 93000000 mph and how long has it been going this speed?
I think the earth is 93000000 miles from the sun and it spins at about 1000 miles per hour hence it is about 24000 miles around and one revolution is one day
How far is 24000 km?
14,913 miles.
How many acres in 24000 square miles?
15,360,000
How fast is the rotation of the earth?
The earth spins at approx 1000 mile per hour. This is quite simple to calculate - the circumference of the planet is 24000 miles approx - and there are 24 hours in a day.
How many miles equal 24000 inches?
Well, there are twelve inches in each foot, so divide 24000 by 12. You have 2000 feet. One mile, is 5280 feet. So, you divide how many feet you have, by how many feet are required. So, 2000 feet / 5280 feet = 0.3787879 miles So, 24000 inches, = 0.3787879 miles. Sincerely, Onel4stkill
Is the force of gravity expierenced by an object fifty miles above the earth the same as if it were on the earth?
No. However at that altitude, it is likely there are some forces of acceleration acting on the object which will affect it.
What is the force of attraction between and object and earth?
Depends upon the size of the object; The Moon (1/6th the size of Earth is 240,000 miles away and causes our Tides (waves in the ocean.)) The Earth causes moon quakes on the moon as well. The biggest object in our Solar System is the SUN (approximately 840,000 miles in diameter and about 93 MILLION miles away) is what holds us in orbit (otherwise we would be a lonely planet floating thru space.)
What is the maximum terminal velocity a free falling object can reach on earth?
The Answer Is Roughly 7 Miles Per Second
Which describes the force on a satellite keeping it in a circular orbit around the earth?
An object in orbit is in what is known as "free-fall". The best way to understand this is to realise that the object has 2 motions: down, and sideways.An object 1000 miles high in orbit will fall down towards the centre of the earth exactly 1000 miles. BUT, in the time it takes it to fall that 1000 miles, it moves EXACTLY 1000 miles sideways, so it is still exactly 1000 miles above the earth. It then falls exactly 1000 miles towards the centre of the earth, but in that time, moves another 1000 miles sideways, so it's STILL 1000 miles above the earth.Now, change that 1000 miles down, for 10 miles, or 1 mile, or 1 inch, AND, change the 1000 miles sideways for 10 miles, 1 mile, 1 inch.The concept of a stable orbit is that for each unit the object moves DOWN, it moves sideways far enough that it is still exactly the same height above the centre of what it is orbiting.
