You need a breaker rated for 10 amps and 250 volts. The breaker must also fit properly in your panel.
A 30 amp circuit on a 250 volt service could handle up to 7500 watts. That's if it's actually 250 volts coming in. You should check that with your meter.
First of all, circuit breakers are rated in amps, not horsepower. Theequivalent between HP and electricity is 1 HP = 746 watts. That is a 1 HP motor requires 746 watts of power to operate it , regardless of the voltage. If you have a 250 amp circuit breaker, it is likely the main breaker to your residential panel. (?) The potential HP the panel could provide could be determined by multiplying the 250 amps times the panels voltage (208,220, 240) and divide the sum by 746.
No, the electrical insulation rating of a 15 amp duplex receptacle is only rated at 130 volts. The 15 amp 240 volt receptacle is rated at 250 volts. The 240 volt receptacle also has a tandem pin configuration instead of the parallel configuration of the 120 volt device. The different pin configuration is so that a 120 volt electrical device can not be plugged into a 240 voltage receptacle.
15, but I wonder if your information is correct. The breaker size doesn't seem to be right and a 240v circuit in a house uses a 2 pole breaker.
The circuit breaker is used to protect the conductor that is connected to it from an overload condition. On a motor load the breaker has to be sized 250% of the motors full load amperage. Some circuits can be only loaded to 80% capacity and this is governed by the sizing of the breaker. Without knowing what the load amperage is, this question can not be answered.
My calculation shows 15 such fixtures on that circuit.
The circuit breaker is sized to the full load amps of the motor times 250%.
The breaker should be sized to 250% of the motor's full load amperage.
A 30 amp circuit on a 250 volt service could handle up to 7500 watts. That's if it's actually 250 volts coming in. You should check that with your meter.
Tripping is caused by excessive current, which is usually the result of a fault in cable or equipment. The circuit breaker is there for safety and it trips to prevent a possible fire starting.
First of all, circuit breakers are rated in amps, not horsepower. Theequivalent between HP and electricity is 1 HP = 746 watts. That is a 1 HP motor requires 746 watts of power to operate it , regardless of the voltage. If you have a 250 amp circuit breaker, it is likely the main breaker to your residential panel. (?) The potential HP the panel could provide could be determined by multiplying the 250 amps times the panels voltage (208,220, 240) and divide the sum by 746.
No, the electrical insulation rating of a 15 amp duplex receptacle is only rated at 130 volts. The 15 amp 240 volt receptacle is rated at 250 volts. The 240 volt receptacle also has a tandem pin configuration instead of the parallel configuration of the 120 volt device. The different pin configuration is so that a 120 volt electrical device can not be plugged into a 240 voltage receptacle.
In this situation, to calibrate a transmitter you need a power circuit and communicator circuit. The Hart communicator used in the calibration process is connected to the power source circuit in parallel. The power source circuit is the one that has ammeter, 250 Ohm resistor, and power source all connected in series. As the transmitter sends output mA, it creates volt drop across the 250 Ohm resister. Let's say the volt drop across the resistor was 1 Volt. Now, back to the Hart communicator. It is a load, meaning there will be a volt drop across the Hart communicator. Since it is in parallel with the power circuit, it is also parallel with the resistor. So, the 1 volt drop across the 250 Ohm resistor will also make 1 volt drop across the Hart communicator. Technically speaking, the 1 volt drop across the Hart communicator is only true if its resistor is also 250 Ohm. However, it does NOT matter what voltage drop is in the Hart communcator. It only sees the "relative" voltage drop changes to measure the changes in transmitter outputs.
15, but I wonder if your information is correct. The breaker size doesn't seem to be right and a 240v circuit in a house uses a 2 pole breaker.
The circuit breaker is used to protect the conductor that is connected to it from an overload condition. On a motor load the breaker has to be sized 250% of the motors full load amperage. Some circuits can be only loaded to 80% capacity and this is governed by the sizing of the breaker. Without knowing what the load amperage is, this question can not be answered.
A circuit breaker is dual function. The only time it will trip is if it senses a fault current that is rated higher than the breaker rating (short circuit). The other trip condition is if the circuit is overloaded and is drawing a current higher than the breaker rating. On breakers that protect motor feeders the breaker has to be rated 250% higher than the motors full load amperage. If the breaker has lots of use and is used for a switch being manually turned off and on will weaken the trip value of the breaker. If you have access to, or know an electrician, a clamp on amp meter on the conductor that the breaker feeds will tell you what is happening. Clamp the line and turn on the load to see exactly what the current is. If, like you say, the breaker is properly rated and the current is within the breaker limits then change out the breaker for a new one.
The formula you are looking for is W = I x E, Watts = Amps x Volts.